Solve for z in the equation above.
z=rwy+x
z=rw+(y/x)
z=y(x+rw)
z=rw-(y/x)
Correct Answer : D
We are asked to make z the subject of the formula.
First, we subtract y/x from both sides of the equation
Thus, the formula for finding the value of z is .
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Correct Answer is C
Explanation
The sides of a right-angled triangle are determined by the Pythagoras theorem. If we let the unknown side to x as in the figure below, then theory is applied as follows.
The value of x is found as:
The value of the unknown leg side of a triangle is about 9.8 feet.
Correct Answer is B
Explanation
The median of the data set is the number that falls in the middle position after arranging the numbers in the data set in the ascending order.
-6, -4, 1, 8, 12
There are 5 numbers in the given data set, therefore the median falls in the third position from either side. Inspecting the data set, 1 fall in the third position, which is the median for the given data set.
Correct Answer is A
Explanation
we are asked to find the percent change in weight gain of a person.
First, we need to find the change in weight gained over the 4 months
Change in weight= 186-176=10 lb
The percent change is expressed as change in weight over original weight *100. Then
The percent change in weight is 6% to the nearest whole number.
Correct Answer is D
Explanation
We are asked to make z the subject of the formula.
First, we subtract y/x from both sides of the equation
Thus, the formula for finding the value of z is .
Correct Answer is D
Explanation
we are asked to find the number of gallons a full tank holds. A full tank is treated as 1 whole.
Letting x be the number of gallons in full tank and setting the proportion equation with the number of gallons on the numerator and fraction of tank on denominator as follows.
Convert the mixed fraction into proper fraction and cross-multiply to find the value of x.
x 1 full tank=185 gallons23full tank
A full tank holds 27/5 gallons, which when converted to a mixed fraction is 5 2/5.
Correct Answer is D
Explanation
In this case, we use a calculator to estimate the positive square root of 42.
Then, multiplying the square root above with 6 becomes
Then, the approximate value of 6 time the positive square root of 42 is 38.9.
Correct Answer is A
Explanation
Choice A: 2 packs of Orange and 2 packs of Cream Soda
- Total drinks: 48 + 24 = 72 drinks
- Total cost: (2 * $15) + (2 * $5) = $30 + $10 = $40
- This choice not only meets the requirement of at least 60 drinks but also offers the best value in terms of cost per drink, making it the most cost-effective option.
Choice B: 3 packs of Root Beer
- Total drinks: 3 * 24 = 72 drinks
- Total cost: 3 * $14 = $42
- While this choice meets the requirement of at least 60 drinks, it's not the most cost-effective, as it costs $42for 72 drinks.
Choice C: 1 pack of Orange, 2 packs of Root Beer, and 1 pack of Cream Soda
- Total drinks: 24 + 48 + 12 = 84 drinks
- Total cost: $9 + (2 * $14) + $5 = $9 + $28 + $5 = $42
- This choice provides more than 60 drinks, but it's not the most cost-effective due to its higher cost of $42, same as choice B.
Choice D: 4 packs of Cream Soda
- Total drinks: 4 * 12 = 48 drinks
- Total cost: 4 * $5 = $20
- While this choice is the most cost effective, it falls short of providing the desired number of drinks.
Correct Answer is D
Explanation
To simplify this expression, we follow the order of operations as follows:
First, we start with the numerator and solve it as follows
[2(6+3*9)]
We start with multiplication in inner brackets, 3 * 9 = 27. The expression becomes
[2(6+27)]
Then, we carry out the addition of 6+27=33. Then, the expression yields
[2(33)]=2*33=66
Now, we solve for denominator, which is 6/2=3.
Thus, the expression is reduced into
The expression reduces into 22.
Correct Answer is A
Explanation
A dependent variable is one that changes when another variable changes. In this case, the cost of the phone will change depending on the change inbrand name, size of the RAM, and size of the battery. Thus, cost of a phone is a dependent variable.
Correct Answer is B
Explanation
By inspection, we find the corresponding values of the given denominations in the following manner.
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