The length of a rectangular room is 5 feet greater than its width. Which of the following equations represents the area (A) of the room?

We are being asked to find the amount of milk needed. This is a proportion problem, which compares the amount of flour to that of milk. Letting x represent the amount of milk required, we set up the proportion with flour on the numerator and amount of milk in denominator as follows:

Change the mixed fraction of 1 1/5 into improper fraction as follows

The proportion equation becomes

Cross-multiply to solve for x

As an mixed fraction, 36/5 becomes 7 1/5. Therefore, 7 1/5 cups of milk are needed to make a big batch of 2 cups.

We use the calculator to determine the positive square root of 20, which is then multiplied by 20.

Using the calculator,

Multiplying the square root above with 10 becomes

The approximate value is 44.7.

In this problem, we need to compare the number of dimes to quarters.

If we let n be number of pennies in the bottle. Then,

Number of quarters in the bottle = 2n

Number of nickels in the bottle = 4n

Number of dimes in the bottle =5(4n)=20n

Now relating dimes to quarters, we have

Thus, there are 10 times as many dimes as quarters in the box.

The probability of an event is determined by the relation

Finding the probability of drawing the red ball, we need to find the total number of balls in the bag.

Total number of balls in the bag=5+4+3=12 balls

The probability of drawing a red ball from the bag is 1/3.

We are asked to convert kg to pounds using the given relation. Letting x to represent the lb we are looking for.

Nest, we set the proportion with kg in the numerator and lb on the denominator as follows.

We find the value of x by cross-multiplication

The value of x is 110 lb.

To find the median, we arrange the following numbers in data set from the smallest to the largest as follows.

-3, -2, 0, 5, 10

From the above the data set, the median falls in the third position. Thus, 0 is the median for the given data set.

We are asked to find the Kwame’s uncle’s age in terms of Kwame’s age.

First, we need to find the age of Kwame, which is k. Then, we know that Kwame’s uncle’s age is three times that of Kwame less 17. Then,

Kwame’s uncle’s age, u = 3k-17.

Thus, the relation that relates Kwame’s uncle’s age to that of Kwame is u=3k-17.

The question requires us to find the percentage change in weight of a person.

First, we need to find the change in weight over the 3 months

Change in weight= 180-160=20 lb

Percent change in weight is change of original weight *100. Thus

The percent change in weight is 11% to the nearest whole number.

To find the greatest number from the given options, we first convert the decimal numbers into fractions.

4.25 becomes 425/100

4.4 becomes 44/10

Then, we find the LCM for the denominators of the given fractions. The LCM of 2, 100, 3 and 10 is 300. Now we can multiply each fraction with the LCM.

9/2*300=1350

425/100*300=1275

10/3*300=1000

44/10*300=1320

Comparing the obtained values from above, 1350 is the greatest followed by 1320, 12750, and 1000 in that order. The fraction 9/2 gave a value of 1350, which was the greatest value. Thus, 9/2 is the greatest value from the given option.

You can also convert to decimals and compare which would give you the same answer.

To find the greatest number from the given options, we first convert the decimal numbers into fractions.

-0.7 becomes 7/10

-1.3 becomes 13/10

Then, we find the LCM for the denominators of the given fractions. The LCM of 3 and 10 is 30. Now we can multiply each fraction with the LCM.

-2/3*30=-20

-7/10*30=-70

-13/10*30=-39

-4/3*30=-40

Comparing the obtained values from above, -20 is the greatest followed by -39, -40, -70 in that order. The fraction -2/3 gave a value of -20, which was the greatest value. Thus, -2/3 is the greatest value from the given option.