Which of the following is the correct decimal placement for the product of 1.6*0.93?

Histograms are used to present frequency of data of one variable over the other. On the other hand, a bar graph is used to compare the two variables with the rectangles not touching one another as in histograms. Scatter plots are used to show the correlations between two variables. In this case, the teacher will be able to use scatter plot to establish the correlation between test scores and the subjects.

to convert fraction to percent, multiply the fraction with 100%. Therefore, the percent equivalent of 3/4 is

3/4*100%=75%

Thus, 3/4is equal to 75%.

we are asked to find the largest value from the options given. To solve this problem, we need to convert all the given values into fraction. Then find the least common denominator for all fractions, which we will use to multiply each fraction and make a comparison.

43÷55=43/55

5/7

0.729=729/1000

73%=73/100

Now, we need to find the least common denominator of 55, 7, 1000, and 100, which is 77000. We multiply each fraction by 77000 as follows:

43/55*77000=60200

5/7*77000=55000

729/1000*77000=56133

73/100*77000=56210

From the calculated values, it can be noted that 43/55 is the greatest value among the given options.

: In order to solve for the value of x, we use the order of operations as follows:

The first step is to divide both sides by 3

Add 2 to both sides to eliminate it from the left-hand side of the equation

x-2+2=4+2

x = 6

Thus, the value of x is 6.

correlations fall into positive, negative, and no correlation. A positive correlation shows that an increase in one variable increase results in an increase on the other variable increases as shown.

A negative correlation scatter plot shows that an increase in one variable results in a decrease on the other one.

The no-correlation scatter plot demonstrates that there is no response between variables. A change in one variable has no effect on the other variable.

Looking at the provided scatter plot, the heights of the students does not have any relationship on the students’ scores. Thus, the type of correlation is no correlation.

Here we need to find the actual values of the additions and see the trend the student will use to estimate the given problem. The exact sum is as follows

35+192=227

258+350=608

947+1032=1979

From the above calculations, it is evident that the student rounds up or down the ones place values. So, in the problem we need to approximate 694+7618.

694+7618=8312

We can approximate 8312 based on the provided choices is 8310.

We need to find how many mL are in 5.5 teaspoons. We are told that 1 teaspoon is about 4.93 mL, which we interpret as follows:

Or

Since we are looking for mL, we use the second option.

Thus, 5.5 teaspoons can hold approximately 27 mL.

We are needed to find the amount Jacob will be left with after spending and reinvesting the rest using the given information.

Amount Jacob spends=87% of $100=87/100*100=$87

Amount left to invest=$(100-87)=$13

Jacob is left with $13, which she invests and earns a profit of 75%.

Profit earned on invested amount=75% of $13=75/100*13=$9.75

So, Jacob will have $13+$9.75=$22.75

 we are to find the selling price of the sweater from the marked price and the discount. The marked price is given as

Discount=mark off rate*original price

Discount=15%*$78

Convert 15% into a fraction, which become 15/100=0.15. Then

Discount=0.15*$78=$11.70

The selling price of the sweater will be the original price less the discount or mark off value. Then,

Thus, the approximate selling price of the sweater is $66.

In this scenario, we use the given chart and scale provided to find the number of each coin and select the right number of coins the student collected.

It is clear that the first choice if the correct answer. The child collected 250 pennies, 200 nickels, 125 dimes, and 25 quarters.