The scatter plot below shows the relationship between the number of hours a student listens to music and the student’s test scores. Which of the following types of correlation is shown on the scatter plot?

The length of the unknown side of the rectangle can be found by using the Pythagoras theorem. We label the triangle from the given data as shown below

Let the unknown length be x.

Applying the Pythagoras theorem, the value of x is found as:

\(a ^2 +b ^2 =c ^2\)

The unknown length of the triangle is approximately 8.9 feet.

To simplify the expression:

12+3×4−1+23

Step 1: Follow the order of operations (BODMAS)

Multiplication first:

3×4=12

23 = 2×2×2=8

Now the expression becomes:

12+12−1+8

Step 2: Perform addition and subtraction from left to right

• 12+12=24
• 24−1=23
• 23+8=31

The correct answer is 31.

here we use the US customary system to convert between yards and feet. We use the conversion 1 yard =3 feet. Then, 6 yards to ft is found as

Thus, 6 yards is equal to 18 ft.

In order to solve for the value of x, we use the order of operations as follows:

The first step is to divide both sides by 4

Since 5 is subtracted, we add 5 to both sides to eliminate it from the left-hand side of the equation

Thus, the value of x is 7.

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous/rangedata. While a bar graph does just fine even with discrete data.

When dealing with percent problems, the following is utilized to find the unknown variable.

• Is means equals
• Of means multiply
• What means unknown (variable)

From the problem above, we are looking for the amount of gratuity the couple can leave.

Let t be the amount of gratuity. Translating into an equation, we have

The gratuity is 15% of the total bill, which becomes

Here, of means multiply and we also convert percent into decimal before multiplying.

So, the value of t=5.76

Thus, a couple will leave a gratuity of $5.76, which is about $6.00.

Based on the above data, the horizontal axis will be tree type and vertical axis will represent the number of trees.

Based on these, a bar graph is appropriate to represent the number trees.

To find the least common denominator (LCD) of the fractions 1/2, 2/3, and 4/5, follow these steps:

Step 1: Identify the denominators

The denominators are 2, 3, and 5.

Step 2: Find the least common multiple (LCM)

The LCM of 2, 3, and 5 is the smallest number that all three denominators divide into evenly.

• Prime factorization:
  • 2=2
  • 3=3
  • 5=5

Since 2, 3, and 5 are all prime numbers, their LCM is:

2×3×5=30

We need to find how many mL are in 2.5 teaspoons. We need to use dimensional analysis to solve this problem as follows.

Converting between teaspoon and mL uses the following conversions:

Or

We want to end up with mL, we utilize the second conversion and set up the following equation.

Thus, 2.5 teaspoons can hold 12.325 mL.

the median of a data set is the element that is found on the middle position. It is found by organizing the elements from the smallest to largest.

The data set above arranged from the smallest to largest is:

11, 12, 12, 12, 13, 14, 17, 17, 18, 22, 26

The number of elements is odd and the median is found in the (N+1)/2 th position. Here N=11, and the median falls in (11+1)/2=12/2=6 th position.

The element 14 falls in the 6th position, which is our median of the given data set.