The scatter plot below shows the relationship between the student’s exam scores and the students’ heights. Which of the following types of correlation is shown on the scatter plot?

 we are to find the selling price of the sweater from the marked price and the discount. The marked price is given as

Discount=mark off rate*original price

Discount=15%*$78

Convert 15% into a fraction, which become 15/100=0.15. Then

Discount=0.15*$78=$11.70

The selling price of the sweater will be the original price less the discount or mark off value. Then,

Thus, the approximate selling price of the sweater is $66.

to find the average time the athlete runs in 1 mile, find total time divided by total distance covered in the two runs.

Total distance=5+3=8 miles

Total time=25+15=40 minutes

We now know that the athlete runs 8 miles in 40 minutes, so the time the athlete will run in 1 mile will be:  

In 5 minutes, the athlete runs 1 mile.

To solve the equation this equation, we use a calculator and find the product as:

3.45 * 0.53= 1.8285

We convert the given word problem into a mathematical expression.

Let the number be x.

Thrice a number = 3x

Twelve less than thrice a number = 3x-12

Thus, the required mathematical expression is 3x-12

The best way to visualize the student’s score for each subject is to plot them using a bar graph.

: a ratio can be thought of a fraction of the form a/b, where b is not equal to zero. In ratio form, to means per.

Now, the class has 26 girls and 22 boys. Thus, the ratio of girls to boys becomes:

The fraction above reduces into

In ratio form, girls: boys=13:11

Thus, the ratio of girls to boys in a class of 48 students is 13 to 11.

Histograms are used to present frequency of data of one variable over the other. On the other hand, a bar graph is used to compare the two variables with the rectangles not touching one another as in histograms. Scatter plots are used to show the correlations between two variables. In this case, the teacher will be able to use scatter plot to establish the correlation between test scores and the subjects.

From the given estimations, we can find the exact sum after adding the given numbers and see the trend the student utilizes to find their estimates. The actual sum is as follows

26+180=206

115+391=506

497+2024=2521

From the above evaluation, the students round the exact sum to the nearest tens. So, in the problem we need to approximate 545+7501.

545+7501=8046

The exact sum is 8046 and the approximate value after rounding to the nearest tens is 8050.

The length of the unknown side of the rectangle can be found by using the Pythagoras theorem. Letting the unknown side to be x, the labelled rectangle becomes: The unknown length of the triangle is about 16.7 feet.

The length of the unknown side of the rectangle can be found by using the Pythagoras theorem. Letting the unknown side to be x, the labelled rectangle becomes:

The unknown length of the triangle is about 16.7 feet.

We usea calculator to find the product of

1.6*0.93=1.488