The table below shows the student’s score at the end of the semester. Which of the following would best display the data?
Subject |
Math |
Chemistry |
Biology |
Physics |
English |
Test scores |
90 |
72 |
85 |
95 |
63 |
Stem and leaf plot
Line graph
Bar graph
Scatter plot
Correct Answer : C
The best way to visualize the student’s score for each subject is to plot them using a bar graph.
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Related Questions
Correct Answer is B
Explanation
To solve this problem, first find the radius of the circle.
Correct Answer is B
Explanation
We follow the order operations to solve for the unknown value of x.
3(2x+5)=11x+5
Open the bracket on the LHS by multiplying each term by 3
(3*2x)+(3*5)=11x+5
6x+15=11x+5
Subtract 15 from both sides
6x+15-15=11x+5-15
6x=11x-10
Subtract 11x on both sides
6x-11x=11x-11x-10
-5x=-10
Divide both sides by -5
-5x/-5=-10/-5
x= 2
Thus, the value of unknown value of x is 2.
Correct Answer is A
Explanation
Correlation of two variables falls into:
Positive correlation: an increase in one variable causes another variable to increase
Negative correlation: an increase in one variable causes another one to decrease
No correlation: a change in one variable does not cause any response in another variable.
From the given choices
Option a is no correlation
Option b is a negative correlation
Option c is a negative correlation
Option d is a positive correlation
Thus, the correct statement is a.
Correct Answer is D
Explanation
correlations fall into positive, negative, and no correlation. A positive correlation shows that an increase in one variable increase results in an increase on the other variable increases as shown.
A negative correlation scatter plot shows that an increase in one variable results in a decrease on the other one.
The no-correlation scatter plot demonstrates that there is no response between variables. A change in one variable has no effect on the other variable.
Looking at the provided scatter plot, the heights of the students does not have any relationship on the students’ scores. Thus, the type of correlation is no correlation.
Correct Answer is D
Explanation
: the question requires we find the cost of four syringes.
If we let x be the cost of four syringes, then we set up a proportion equation with cost as numerator and number of syringes as denominator. The proportion equation becomes
Cross-multiply to solve for x
Rearranging the above
Divide both sides of the equation by 55
Thus, the cost of 4 syringes is $48.
Correct Answer is A
Explanation
: In order to solve for the value of x, we use the order of operations as follows:
The first step is to divide both sides by 3
Add 2 to both sides to eliminate it from the left-hand side of the equation
x-2+2=4+2
x = 6
Thus, the value of x is 6.
Correct Answer is A
Explanation
we are asked to find the largest value from the options given. To solve this problem, we need to convert all the given values into fraction. Then find the least common denominator for all fractions, which we will use to multiply each fraction and make a comparison.
43÷55=43/55
5/7
0.729=729/1000
73%=73/100
Now, we need to find the least common denominator of 55, 7, 1000, and 100, which is 77000. We multiply each fraction by 77000 as follows:
43/55*77000=60200
5/7*77000=55000
729/1000*77000=56133
73/100*77000=56210
Â
From the calculated values, it can be noted that 43/55 is the greatest value among the given options.
Â
Correct Answer is D
Explanation
We need to find how many mL are in 5.5 teaspoons. We are told that 1 teaspoon is about 4.93 mL, which we interpret as follows:
     Â
Or
    Â
Since we are looking for mL, we use the second option.
    Â
Thus, 5.5 teaspoons can hold approximately 27 mL.
Correct Answer is D
Explanation
When solving percent problems, the following words and their meaning becomes handy.
- Is means equals
- Of means multiply
- What means unknown (variable)
If we let x represent the amount of tip the couple want to leave behind, then
So, the couple will leave a tip of $2.84, which is about $3.00
Correct Answer is B
Explanation
Histograms are used to present frequency of data of one variable over the other. On the other hand, a bar graph is used to compare the two variables with the rectangles not touching one another as in histograms. Scatter plots are used to show the correlations between two variables. In this case, the teacher will be able to use scatter plot to establish the correlation between test scores and the subjects.
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