There are 800 students enrolled in four allied health programs at a local community college. The percent students in each program are displayed in the pie chart. Which of the following is the number of students enrolled in the nursing program?

168
144
336
152
Correct Answer : C
we are asked to find the number of students enrolled in the nursing program using the percentages in the pie chart.
If we let x represent the number of students enrolled in the nursing program, we set a proportion equation with number of students on the numerator and percentages on the denominator.
Total percent in the pie chart is 100%, which equals 800 students. Then, 42% will represent

We solve the value of x by cross-multiplying the equation above.

Therefore, 336 students will enroll for a nursing program.
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Related Questions
Correct Answer is D
Explanation
To find the greatest number from the given options, convert the decimal numbers into fractions.
6.25 becomes 625/100
7.4 becomes 74/10
The LCM for the denominators of 8, 100, 7, and 10 is 2800. Now we can multiply each fraction with the LCM.
3/8*2800=1050
625/100*2800=17500
10/7*2800=4000
74/10*2800=20720
The fraction 7.4is the greatest of all.
Correct Answer is A
Explanation
we find the value of x by applying the absolute conditions to the given equation.
First, add 2 to both sides of equation

Add 10 to both sides of the equation

Next, we apply the absolute rule:
If u=a
, a>0, then u=a or u=-a
In this case a=5, which is greater 0.
The first condition becomes

Solving for x

The second condition becomes

Solving for x


Then, the value of x is -4/3 or 2.
Correct Answer is C
Explanation
A standard six-sided die has the numbers 1, 2, 3, 4, 5, and 6. The even numbers are 2, 4, and 6.
Step 1: Probability of rolling an even number on the first roll
There are 3 even numbers out of 6 total numbers, so:
P (evenonsecondroll) = 3/6 = ½
Step 2: Probability of rolling an even number on the second roll
Since rolling the die is an independent event, the probability remains:
P (evenonsecondroll) = 3/6 = ½
Step 3: Multiply the probabilities
P (evenonfirstANDevenonsecond) = ½ × ½ = ¼
Correct Answer is D
Explanation
The range of a data set is calculated as:
Range=MaximumValue−MinimumValue
From the given bar graph:
- The minimum number of goals scored is 0.
- The maximum number of goals scored is 5.
Thus, the range is:
5−0=5
Correct Answer is D
Explanation
9/26 is equivalent to 9÷26. The value becomes 0.3461538.
Thus, 0.35is the decimal equivalent of 9/26.
Correct Answer is D
Explanation
We are asked to determine John’s uncle’s age relating to John’s age.
First, express John’s uncle’s age in terms of John’s age as follows
John’s age=k
John’s uncle’s age, u = 5k-12.
Thus, the relationship between Japheth’s uncle’s age to that of Japheth is u=5k-12.
Correct Answer is D
Explanation
the mean of a data set is the total scores divided by the number of tests.
Total test scores =80+68+74+87+96=405
Number of tests =5
Mean test score =405/5=81
The mean test score is 81.
Correct Answer is D
Explanation
 we use the calculator to determine the positive square root of 20, which is then multiplied by 20.
Using the calculator,
 
Multiplying the square root above with 5 becomes

The approximate value is 26.9.
Correct Answer is A
Explanation
A histogram depicts the frequency of a one variable over the other while a bar graph is used to compare two variables with vertical axis representing the heights. Therefore, a histogram will be used to represent percent of the number of students reading after 9.
Correct Answer is C
Explanation
we are asked to find the number of students enrolled in the nursing program using the percentages in the pie chart.
If we let x represent the number of students enrolled in the nursing program, we set a proportion equation with number of students on the numerator and percentages on the denominator.
Total percent in the pie chart is 100%, which equals 800 students. Then, 42% will represent

We solve the value of x by cross-multiplying the equation above.

Therefore, 336 students will enroll for a nursing program.
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