To determine the insurance of a car, an insurance company considers the following determinants: the age of the car, the model of the car, and the mileage of the car. Which of the following is the dependent variable?

We solve the problem by first finding the amount of gallons needed for the whole trip then find the cost of the gallon.

The car uses 1 gallon to cover 25 miles, which is same as:

Now, in 3000 miles, the car will use how many gallons of gasoline?

A trip of 3000 miles will need 120 gallons. And to find the cost of 120 gallons, we proceed as follows:

The family will spend $199.20 to drive for 3000 miles.

We can interpret ‘cannot exceed” as less than ‘<’. Therefore, in our inequality, the symbol < must be included. Now let’s convert the word problem into a mathematical inequality.

Money spent on supplies=s

Money spent on textbooks=t

Total money spent=money spent on supplies + money spent on textbooks

Total money spent = s+t

But the money spent cannot exceed $12,000. Then,

s+t <$12,000.
However the money spent can still be equal to $12000, as it has not exceeded it.

Therefore, therequired inequality is s + t <= $12,000.

We extrapolate the values of a line between 10 and 15 on y-axis to meet the curve and drop another line from the intersection of the curve to meet the x-axis and read off the age of the car.

Now, let’s extrapolate in the following diagram

The intersection of the line and the x-axis is between 4 and 5 years. This means that the car is about 4.5 years old. From the options given, the age of the car is more than 3 years old.

From the given options, we can arrange the numbers from the smallest to the largest as:

-271.906, -193.823, 145.884, 235.971

From the above, it can be noted that -271 is less than -193 while 235 is more than 145.

Round trip means to and from, which is twice the distance from home to a medical facility.

In one day, the round trip=19+19=38 miles

So, in 22 days, the round trip=38*22=836 miles.

The patient will cover 836 miles in 22 days.

A whole pizza is equivalent to 1. Then

One friend eats half of the pizza=1/2 of 1=1/2*1=1/2

Remaining amount of pizza to be shared=1-1/2=2/2-1/2=1/2

Now, three friends share ½ equally and each friend will get,

Thus, the three friends each share 1/6.

to do a comparison of the given data set, we convert the fraction numbers into the approximate decimals.

4/3=1.333

2720=1.35

Now, we have 1.333, 1.35, 1.369, 1.357. These numbers are arranged from the smallest to the largest number, we look at the number in the second decimal place value

1.333 the number in second decimal place value is 3

1.35 the number in third decimal place value is 5

1.369 the number in third decimal place value is 6

1.357 the number in third decimal place value is 5

However, 1.35 and 1.357 have 5 in the second-place vale. We use the ird place value to compare the two number:

1.35 is same as 1.350 and the number in the third-place value is 0

1.357 the number in the third-place value is 7

Now, 0 is less than 7, and thus 1.35 is less than 1.357

Overall, 3 is less than 5, and 5 less than 6 and the provided numbers can be arranged from the smallest to the largest as:

1.333, 1.35, 1.357, 1.369

Thus, the corresponding given numbers organized from the smallest to the largest become:

4/3, 27/20, 1.357, 1.369

The greatest value is 1.369

Here we collect like terms together and solve for the unknown value of x.

7x-6=3x-26

Add 6 to both sides of the equation

7x-6+6=3x-26+6

7x=3x-20

Subtract 3x from both sides of the equation

7x-3x=-20

4x=-20

Divide both sides by 4

4x/-4=-20/4

x = -5

The value of x = -5

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous data. While a bar graph does just fine even with discrete data.

Let xxx be the amount the friend paid for their car. The problem states:

48,000=2x−2,000

Step 1: Solve for x

Add 2,000 to both sides:

48,000+2,000=2x

Divide by 2:

x=25,000