When the marks of a science test are graphed, the distribution of markss is symmetric with the majority of weights centered around a single peak. Which of the following describes the shape of this distribution?
Uniform
Skewed right
Bell-shaped
Bimodal
Correct Answer : C
In a bell-shaped curve, the data distribution is symmetric around a single peak. The centering of data around a single peak means the mean, mode and median of the test are all equal to each other.
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Correct Answer is A
Explanation
The truck carries a whole cargo which equals 1. If we let the weight of the cargo to be p, then we set up a proportion equation with weight as numerator and fraction of cargo as denominator.

Solve for value of p by cross products

Multiply both sides by 3/2 a reciprocal of 2/3


The truck carries a cargo weighing 795 lb.
Correct Answer is A
Explanation
The selling price of the sweater is marked price less the mark off value.
Mark off value=mark off rate*original price
Mark of value=30% of $95
Mark of value=0.30*$95=$28.50
Now, find the selling price of the sweater
Selling price= marked price-mark off value

Thus, the sweater will be sold for 66.50 after applying a mark off of 30%. The selling price is about $67.
Correct Answer is C
Explanation
In this problem, we need to find the amount of gratuity the couple will leave. The gratuity is 16% of the total bill. Before solving the problem, the following are terms and their meaning in percent problems:
- Is means equals
- Of means multiply
- What means unknown (variable)
If we let x be the amount of gratuity, then translating the given problem into a mathematical equation becomes:

Now we evaluate the above equation noting that of means multiply.

So, the value of x=9.376 and to the nearest cent, x=9.38
There, a couple will leave a gratuity of $9.38.
Correct Answer is A
Explanation
We analyze the given statement with the graph given as follows:
For option a: the points per game decreased five times between 1996 and 2015. So, the statement is true.
For option b: the lowest points scored per game was in 1998-99 season. So, the statement is false.
For option c: 2008-09 was the season the chargers scored the greatest number of points per game and not 2002-03 as claimed in the statement. So, this statement is not true.
Correct Answer is C
Explanation
From the given data, we can draw the following triangle by letting the unknown length to be p.

We apply the Pythagoras theorem, the value of p:

The unknown length of the triangle is about 21.4 feet.
Correct Answer is C
Explanation
We need to find the amount Lana left after spending and investing another.
Lana spends=70% of $90=70/100 * 90 = $63
Amount left after spending=$(90-63) = $27
Lana is left with $27, which she will invest and earns a profit of 60%.
Profit earned=60% of $27 = 60/100 * 27 = $16.20
Therefore, Lana will have $27 + $16.20 = $43.20
Correct Answer is D
Explanation
Here we need to find the actual values of the additions and see the trend the student will use to estimate the given problem. The exact sum is as follows
35+192
227
258+350=608
947+1032=1979
From the above calculations, it is evident that the student rounds up or down the ones place values. So, in the problem we need to approximate 694+7618.
694+7618=8312
We can approximate 8312 based on the provided choices is 8310.
Correct Answer is D
Explanation
We use 1 L =1000 mL to convert between the two units. The conversion options of interconversions are:

And

We want millimeters, use the second option to change L to mL as:

Therefore, 2.5 L is equivalent to 2500 mL.
Correct Answer is B
Explanation
The initial step is to convert the decimal numbers into fractions.
5.2 becomes 52/10
5.15 becomes 515/100
Next, find the least common denominator of 3, 10, and 100, which is 300. We use this value and multiply each fraction.
7/3*300=700
52/10*300=1560
13/3*300=1300
515/100*300=1545
From the above, 1560 is the greatest value which corresponds to 52/10. Thus, 5.2 is the greatest value of all the choices given.
Correct Answer is B
Explanation
In this scenario, we use the given scale in the charts to find the number of each coin and selected the right number of coins the student collected.

From the above evaluations, option two is the correct choice.
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