When the marks of a science test are graphed, the distribution of markss is symmetric with the majority of weights centered around a single peak. Which of the following describes the shape of this distribution?

To change between L and mL, the following two options are used.

The first five months of the year are January, February, March, April, and May. We use to graph to find the amount of rainfall in each month as follows:

In the month of January, rainfall was between o and 1, which is halfway. Therefore, rainfall in January is 0.5 inches

On February, rainfall was 1 inch and on March the rainfall was 2 inches.

On April, the rainfall amount was 4 inches while on month of May, the rainfall was about 3.5 inches. Therefore, total rainfall in the first 5 months was:

Total rainfall=0.5 inches+1 inches+ 2 inches+4 inches + 3.5 inches =11 inches

In this problem, we need to find the amount of gratuity the couple will leave. The gratuity is 16% of the total bill. Before solving the problem, the following are terms and their meaning in percent problems:

• Is means equals
• Of means multiply
• What means unknown (variable)

If we let x be the amount of gratuity, then translating the given problem into a mathematical equation becomes:

Now we evaluate the above equation noting that of means multiply.

So, the value of x=9.376 and to the nearest cent, x=9.38

There, a couple will leave a gratuity of $9.38.

In a bell-shaped curve, the data distribution is symmetric around a single peak. The centering of data around a single peak means the mean, mode and median of the test are all equal to each other.

In the given problem, we use the calculator to evaluate the product 1.9 * 0.75 = 1.425

We solve for the value of x by following the order of operations

3(x-2)=15

Divide both sides of the equation by 3

Add 2 to both sides of the equation

Thus, the value of x is 8.

The median of a data set is found in two ways:

For an odd data set, the median fall in the (N+1)/2 th position.

For an even data set, the median is the average of the element in the (N/2)th and (N+1)/2 th positions.

To find the median of the given data set, we need to arrange the elements from the smallest to the largest as follows:

12, 12, 16, 18, 19, 22, 23, 24, 26, 35, 35

There are 11 elements in the data set. 11 is an odd number and the median fall in the (N+1)/2 th position.

Median =(11+1)/2=12/2=6 th position.

From the organized data, the element in the 6th position is 22, which is the required median for the data set.

A ratio is of the form a : b but can also be converted to a fraction of the form a/b, where b is not equal to zero. Besides, to in ration means per in fraction form.

In the class of 40 students, 22 are girls and 18 are boys. Thus, the ratio of girls to boys becomes:

The above fraction can be reduced further since 2 is a common factor in both 22 and 18. Thus

In ratio form, girls: boys=11:9

Thus, the ratio of girls to boys in a class of 40 students is 11 to 9.

To form an equation from the word problem, first break the given statement into smaller statements.

First, we are given the width of the rectangle as x. We are told, the length is three times width. Mathematically, this means

Length=3*width=3*x=3x

Again, the length is 4 less than 3 times width of the rectangle. Thus, the length of rectangle in terms of width becomes:

Length =3x-4

This is the required equation.

to find the average time the athlete runs in 1 mile; we find total distance and total time the athlete takes in running.

Total distance run by athlete=7+3=10 miles

Total time=45+15 =60 minutes

The athlete runs 10 miles in 60 minutes. For the athlete to cover 1 mile, he will run for a time less than 60 minutes. Thus, in 1 mile, the athlete takes:

So, in 6 minutes, the athlete covers 1 mile.