When the marks of a science test are graphed, the distribution of markss is symmetric with the majority of weights centered around a single peak. Which of the following describes the shape of this distribution?

We analyze the given statement with the graph given as follows:

For option a: the points per game decreased five times between 1996 and 2015. So, the statement is true.

For option b: the lowest points scored per game was in 1998-99 season. So, the statement is false.

For option c: 2008-09 was the season the chargers scored the greatest number of points per game and not 2002-03 as claimed in the statement. So, this statement is not true.

We two conversions when asked to convert between kg and lb

And

We need kg equivalent of 220 lb, therefore we use option 1 and carry out the conversions as follows:

Thus, 100kg is equal to 220lb.

to find the average time the athlete runs in 1 mile; we find total distance and total time the athlete takes in running.

Total distance run by athlete=7+3=10 miles

Total time=45+15 =60 minutes

The athlete runs 10 miles in 60 minutes. For the athlete to cover 1 mile, he will run for a time less than 60 minutes. Thus, in 1 mile, the athlete takes:

So, in 6 minutes, the athlete covers 1 mile.

Here we need to find the actual values of the additions and see the trend the student will use to estimate the given problem. The exact sum is as follows

35+192227

258+350=608

947+1032=1979

From the above calculations, it is evident that the student rounds up or down the ones place values. So, in the problem we need to approximate 694+7618.

694+7618=8312

We can approximate 8312 based on the provided choices is 8310.

The selling price of the sweater is marked price less the mark off value.

Mark off value=mark off rate*original price

Mark of value=30% of $95

Mark of value=0.30*$95=$28.50

Now, find the selling price of the sweater

Selling price= marked price-mark off value

Thus, the sweater will be sold for 66.50 after applying a mark off of 30%. The selling price is about $67.

The first five months of the year are January, February, March, April, and May. We use to graph to find the amount of rainfall in each month as follows:

In the month of January, rainfall was between o and 1, which is halfway. Therefore, rainfall in January is 0.5 inches

On February, rainfall was 1 inch and on March the rainfall was 2 inches.

On April, the rainfall amount was 4 inches while on month of May, the rainfall was about 3.5 inches. Therefore, total rainfall in the first 5 months was:

Total rainfall=0.5 inches+1 inches+ 2 inches+4 inches + 3.5 inches =11 inches

The truck carries a whole cargo which equals 1. If we let the weight of the cargo to be p, then we set up a proportion equation with weight as numerator and fraction of cargo as denominator.

Solve for value of p by cross products

Multiply both sides by 3/2 a reciprocal of 2/3

The truck carries a cargo weighing 795 lb.

To solve the equation this equation, we compute the multiplication of the two numbers using the calculator

3.60 * 0.75 = 2.7

We use given information to find how much ammonia is need to make the specified solution.

We are told, one gallon of cleaning solution requires 10oz of ammonia. Expressing this mathematically yields two options:

\(\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\)or\(\frac{1\ gallon\ of\ solution}{10\ oz\ of\ ammonia}\)

Now we find how much ammonia is needed using option two.

\(51\ gallon\ of\ solution\ *\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\ =\ 510\ oz\ of\ ammonia\)

From the above equation, gallon of solution will cancel, and oz of ammonia is left.

Therefore, the solution will require 510 oz of ammonia.

The median of a data set is found in two ways:

For an odd data set, the median fall in the (N+1)/2 th position.

For an even data set, the median is the average of the element in the (N/2)th and (N+1)/2 th positions.

To find the median of the given data set, we need to arrange the elements from the smallest to the largest as follows:

12, 12, 16, 18, 19, 22, 23, 24, 26, 35, 35

There are 11 elements in the data set. 11 is an odd number and the median fall in the (N+1)/2 th position.

Median =(11+1)/2=12/2=6 th position.

From the organized data, the element in the 6th position is 22, which is the required median for the data set.