Which of the following is an appropriate unit of measure to express the length of a chair?

The mean of a data set is the sum of all scores divided by the number of tests.

Total test scores = 83+86+76+88+97 = 430

Number of tests = 5

Mean test score = 430/5 = 86

The mean test score is 86.

Based on the given scenario, the outcome of measuring the daily dollar rate is the decline in investment, stock prices, and forex exchange. The three outcomes are dependent variables while the dollar rate is the independent variable.

To find the cheapest option, we find the amount the consume will spend for each option given.:

• 2 packs of Orange and 1 pack of Cream Soda will cost $16+$5= $21
• 3 Packs of Orange will cost $16+$12=$28
• 2 packs of Root Beer and 1 pack of Cream Soda will cost 2($15)+$7=$37
• 5 packs of cream Soda will cost 5($7)=$35

From the above evaluation, the cheapest option will cost the consumer $21. Thus, buying 2 packs of Orange and 1 pack of Cream Soda will be cheaper to purchase compared to other options.

C organizes the collection correctly.

The median of a data set is a number that falls in the middle of the data set. To find the median, the numbers in the data set are arranged from the smallest to the largest. In the given data set, the organized arrangement is:

-5, -1, 0, 3, 9

There are five elements in the data set, and the median falls in the third position from either side. Thus, 0 falls in the third position.

We use the given slope to find the minimum length of the ramp. In this case, slope is the ratio of height to length of the lamp. Thus,

If we let x be the minimum length of the ramp. Then,

Substituting the value of slope into the above equation results in,

Solve for value of x by cross-products

X = 18 Feet

Thus, the minimum length of the ramp needed to provide access to a door that is 1.5 high is 18 feet.

Given the equation A(f)=92+2f

To find the value of A(f), we need to manipulate the value of f. In this case, f is the independent variable while A(f) is the dependent variable.

we are asked to find the number of gallons a full tank can hold. A full tank is equivalent to 1.

Convert the mixed fraction into proper fraction as follows

(2frac{2}{5}=frac{left(2ast5 ight)+2}{5}=frac{10+2}{5}=frac{12}{5})

If we let x be the number of gallons in full tank, and setting up the proportion equation with the number of gallons on the numerator and fraction of tank on denominator as follows.

(frac{x gallons}{1 full tank}=frac{frac{12}{5} gallons}{frac{4}{7}full tank})

Cross-multiply to find the value of x.

(frac{x }{1 full tank}=frac{frac{12}{5} gallons}{frac{4}{7}full tank})

(x astfrac{4}{7}full tank=frac{12}{5} gallonsast1 full tank)

(x =frac{frac{12}{5} gallonsast1 full tank}{frac{4}{7}full tank}=frac{12}{5}divfrac{4}{7} gallons=frac{12}{5}astfrac{7}{4}gallons=frac{21}{5}gallons)

Converting 21/5 to a mixed fraction is 4 1/5. Thus, when the tank is full, it holds 4 1/5 gallons of water.

We are asked to find the number of cups of flour that will be used to make 90 cookies.

First, we convert 2 ¼ into improper fraction as:

Letting x to be the number of cups of flour, we set up a proportion equation with number of cookies on numerator and number of cups of flour on the denominator becomes:

Solve the value of x by cross-products

Dividing both sides by 60, the above equation result to

Thus, the number of cups of flour needed to make 90 cookies is 81/16 cups, which is equal to 5 1/16 cups.

The number of cups of milk to make a bigger batch, we proceed as follows:

First convert the mixed number 1 2/5 as

Then, we let the unknown number of cups of milk to be x and we set a proportion equation with number cups of floor as numerator and cups of milk as denominator

Find the value of x by cross-products

2 as a fraction is 2/1 which is then used to find the product of the numerator as follows.

Per means division. The above equation becomes

When dividing fractions, we multiply the first fraction with the reciprocal of the second. The reciprocal of 2/9 is 9/2. Thus

The numbers of cups of milk required is 63/5, which when converted to mixed fraction becomes 12 3/5.