Which of the following is an appropriate unit of measure to express the length of a width of a window?

The number of boxes to fit the room is found as volume of the room divided by the volume of the box.

Number of boxes:

\(\frac{volume\ of\ the\ room}{volume\ of\ the\ box} = \frac{12ft\ *\\ 12ft\ *\ 12ft}{2.5ft\ *\ 2.5t\ *\ 2.5ft}\ =\ 110.592\)

The approximate number of boxes that can be stored in the room is approximately 111 square feet.

percentages are fractions with denominator equal to 100. Then, in decimal form:

The decimal form of 67.9% is 0.679.

An independent variable is a variable that is manipulated or changed in the experiment. From the given equation, x is variable that is changed to obtain the desired outcome, F(x). Therefore, x is an independent variable.

A dependent variable is one that changes when another variable changes. In this case, the cost of the phone will change depending on the change inbrand name, size of the RAM, and size of the battery. Thus, cost of a phone is a dependent variable.

We are tasked to find the unknown values of x in the given equation.

First, we add 8 to both sides of the equation.

Next, we apply the absolute rule:

If   , a>0, then u=a or u=-a

From our resulting equation, a=14, which is greater 0. Then, the first condition (u=a) becomes

Solving for x

The second condition (u= -a) becomes

Solving for x

Thus, the value of x is 4 or -3

in this case, we express James’ uncle’s age in terms of James’ age. From the equation:

James’ age is n

James’s uncle’s age is m=3n-13

Thus, the relation that relates James’ uncle’s age in terms of James’ age is m=3n-13.

By inspection, we find the corresponding values of the given denominations in the following manner.

the mean of a data set is the sum of the scores divided by the number of tests.

Total test scores =99+93+67+ 48+ 92+ 87=486

Number of tests =6

Mean test score =486/6=81

The mean test score is 81.

We required to find the units of finding the weight of a sheet of paper. The SI unit of mass of an object is kilogram. However, kilogram is a large quantity that cannot be used to measure smaller objects.

Thus, derived units of mass are used to find the mass of other objects. In this case, the mass of a sheet paper can be recorded in grams.

To find the greatest number from the given set, we first convert the decimal numbers into fractions.

12.35 becomes 1235/100

11.46 becomes 1146/10

Then, the LCM for the denominators of the given fractions of 2, 100, 3 and 10 is 300. Now we multiply each fraction with 300, which we will use to compare the give set.

25/2*300=3750

1235/100*300=3705

40/3*300=4000

1146/10*300=3438

From the calculated values, 4000 is the greatest value. Then, 40/3is the greatest value.