**Which of the following is the appropriate estimate of 1 teaspoon?**

0.5 L

50 mL

5 L

5 mL

*Correct Answer : D*

A teaspoon can approximately hold 5 mL.

Although the capacity of a teaspoon could be more or less, choice D remains the most correct answer as the other choices have amounts too much for a small teaspoon.

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Related Questions

### Correct Answer is B

#### Explanation

A dependent variable is one that when another variable changes, it also changes. In our case, the insurance premium changes if the age, model, mileage of car changes. Thus, insurance premium is the dependent variable while the other three are independent variable.

### Correct Answer is A

#### Explanation

We are given a mix of fractions and decimals and to compare the numbers, we convert the given decimals to fractions.

4.4 becomes 44/10

4.25 becomes 425/100

Now the set of fractions for comparison are: 9/2, 10/3, 44/10, and 425/100. The least common denominator for 2, 3 and 10 is 300. Then,

9/2*300=1350

10/3*300=1000

44/10*300=1320

425/10*300=1275

From the above products, 9/2 gives the greatest value when the fractions are compared with the least common denominator of the given denominators.

### Correct Answer is C

#### Explanation

We extrapolate the values of a line between 10 and 15 on y-axis to meet the curve and drop another line from the intersection of the curve to meet the x-axis and read off the age of the car.

Now, let’s extrapolate in the following diagram

The intersection of the line and the x-axis is between 4 and 5 years. This means that the car is about 4.5 years old. From the options given, the age of the car is more than 3 years old.

### Correct Answer is D

#### Explanation

A teaspoon can approximately hold 5 mL.

Although the capacity of a teaspoon could be more or less, choice D remains the most correct answer as the other choices have amounts too much for a small teaspoon.

### Correct Answer is D

#### Explanation

Here, the athlete runs 6 miles in 51 minutes, which can be expressed as:

Now, in 90 minutes, the athlete will cover about

Therefore, the athlete runs about 10.6 miles in 90 minutes.

### Correct Answer is A

#### Explanation

From the given options, we can arrange the numbers from the smallest to the largest as:

-271.906, -193.823, 145.884, 235.971

From the above, it can be noted that -271 is less than -193 while 235 is more than 145.

### Correct Answer is B

#### Explanation

from the provided table, the first option represents the amount of gas in gallons while the second column shows the distance in miles. Thus, (6, 144) will denote that the car can 144 miles by consuming 6 gallons of a gas.

### Correct Answer is D

#### Explanation

we use the US customary system of unitsâ€™ equivalent to convert from yards to inches. We know that 1yard=3 ft, and 1 ft =12 inches.

First, convert 2 Â¾ into an improper fraction.

Then,

### Correct Answer is A

#### Explanation

to do a comparison of the given data set, we convert the fraction numbers into the approximate decimals.

4/3=1.333

2720=1.35

Now, we have 1.333, 1.35, 1.369, 1.357. These numbers are arranged from the smallest to the largest number, we look at the number in the second decimal place value

1.333 the number in second decimal place value is 3

1.35 the number in third decimal place value is 5

1.369 the number in third decimal place value is 6

1.357 the number in third decimal place value is 5

However, 1.35 and 1.357 have 5 in the second-place vale. We use the ird place value to compare the two number:

1.35 is same as 1.350 and the number in the third-place value is 0

1.357 the number in the third-place value is 7

Now, 0 is less than 7, and thus 1.35 is less than 1.357

Overall, 3 is less than 5, and 5 less than 6 and the provided numbers can be arranged from the smallest to the largest as:

1.333, 1.35, 1.357, 1.369

Thus, the corresponding given numbers organized from the smallest to the largest become:

4/3, 27/20, 1.357, 1.369

The greatest value is 1.369

### Correct Answer is D

#### Explanation

Percentages always add up to 100%. If we let x be the percent of graduates working for jobs unrelated to law, then

74%+3%+2%+x=100%

79%+x=100%

Subtract 79% from both sides of the equation

79%-79%+x=100%

x=100%-79%

x=21%

So, the number of graduates working for jobs unrelated to law is 21%.

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