Which of the following is the appropriate estimate of 1 teaspoon?
0.5 L
50 mL
5 L
5 mL
Correct Answer : D
A teaspoon can approximately hold 5 mL.
Although the capacity of a teaspoon could be more or less, choice D remains the most correct answer as the other choices have amounts too much for a small teaspoon.
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Related Questions
Correct Answer is A
Explanation
We are given that 1 teaspoon=4.93 mL, we can interpret it as:

Or

Since we are to find the amount in mL, we look for an option that will cancel teaspoon and remain with mL. The second option is the required conversion, and we proceed as follows:

Therefore, 2.5 teaspoons hold about 12.325 mL.
Correct Answer is A
Explanation
Let xxx be the amount the friend paid for their car. The problem states:
48,000=2x−2,000
Step 1: Solve for x
Add 2,000 to both sides:
48,000+2,000=2x
Divide by 2:
x=25,000
Correct Answer is A
Explanation
Here we collect like terms together and solve for the unknown value of x.
7x-6=3x-26
Add 6 to both sides of the equation
7x-6+6=3x-26+6
7x=3x-20
Subtract 3x from both sides of the equation
7x-3x=-20
4x=-20
Divide both sides by 4
4x/-4=-20/4
x = -5
The value of x = -5
Correct Answer is B
Explanation
The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.
Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.
As you can see below, the Histogram is used to depict a pattern/continuous data. While a bar graph does just fine even with discrete data.


Correct Answer is C
Explanation
In this problem, to find one side of the square garden, we use the calculator to find the square root of 13. Thus

Thus, the approximate side of a square garden is about 3.6 ft
Correct Answer is A
Explanation
From the given options, we can arrange the numbers from the smallest to the largest as:
-271.906, -193.823, 145.884, 235.971
From the above, it can be noted that -271 is less than -193 while 235 is more than 145.
Correct Answer is D
Explanation
A teaspoon can approximately hold 5 mL.
Although the capacity of a teaspoon could be more or less, choice D remains the most correct answer as the other choices have amounts too much for a small teaspoon.
Correct Answer is D
Explanation
We can interpret ‘cannot exceed” as less than ‘<’. Therefore, in our inequality, the symbol < must be included. Now let’s convert the word problem into a mathematical inequality.
Money spent on supplies=s
Money spent on textbooks=t
Total money spent=money spent on supplies + money spent on textbooks
Total money spent = s+t
But the money spent cannot exceed $12,000. Then,
s+t <$12,000.
However the money spent can still be equal to $12000, as it has not exceeded it.
Therefore, therequired inequality is s + t <= $12,000.
Correct Answer is B
Explanation
In the simple interest, we utilize the following formula to find the simple interest after a period of time in years.
I=P*r*t
I is the interest
P=Principal or initial deposit
r=rate
t=time in years
From the given problem, P=$600, r=6%=6/100=0.06, t=5 years. Then
I=$600*0.06*5=$180
After 5 years, Pat will earn an interest of $180.
Correct Answer is B
Explanation
The median temperature can be found by organizing the temperature values from the smallest to the largest value as follows:
98.6, 98.7, 99.0, 99.0,99.2, 99.3, 99.7, 100.0
(for an even set of numbers, Median = frac{(frac{n}{2})th observation + (frac{n}{2} + 1) th observation}{2})
From the data set above, there are 8temperature values. The median is the temperature value in the middle position, which falls between the(frac{n}{2} th)and((frac{n}{2} + 1) th) position. Here N=8and median is found as:
(frac{(frac{n}{2})th + (frac{n}{2} + 1) th}{2} = )(frac{(frac{8}{2})th + (frac{8}{2} + 1) th }{2} = 4.5th position)
The element in the 4.5th position is the average of the 4th and 5th element.
(frac{99.0 + 99.2}{2} = 99.1)
Thus 99.1 is the median temperature.
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