Which of the following is the best estimate in meters for the average width of a doorway?

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous/rangedata. While a bar graph does just fine even with discrete data.

In this case, we are measuring average weight of the babies with time. The weight of the babies will vary with time, meaning when we vary time, the average weight of the babies will be different. Here, time is independent while average weight is dependent variable.

Step 1: Find a common denominator

The least common denominator (LCD) of 6 and 3 is 6.

Convert 4/3​ to have denominator 6:

4/3=8/6

Step 2: Add the fractions

5/6+8/6=13/6​

Step 3: Convert to a mixed number

13/6 = 2 1/6

The best estimate is about 2 ½ cups.

The decimal equivalent of the percentage is the percentage value divided by 100. Thus

87.5%=87.5/100=0.875

Given:
- Original price of the recliner: P
- Sale price (30% less than the original price): 0.7P
- Coupon saves an additional 25% off the sale price: 0.75 *0.7P = 0.525P
- The consumer pays $237 for the recliner.

We set up the equation:
0.525P = 237

Now, let's solve for P:

P = 237 / 0.525}
P = 451.428

Rounded to the nearest dollar, the original price of the recliner is approximately 451dollars.

Number of boxes in the room is equal to the volume of the room divided by the volume of one box

Volume of the room=9 ft*9 ft*9 ft= 729 ft3

Volume of one box = 2 ft* 2 ft * 2 ft= 8 ft3

Number of boxes= 729 ft3/ 8 ft3= 91.125 boxes

Thus, the room can store 91.125 boxes, which is about 91 boxes.

However, the room’s dimensions are 9 ft x 9 ft x 9 ft, and the boxes are 2 ft x 2 ft x 2 ft. To determine how many boxes fit along each dimension:

• In the 9 ft length, you can fit\(\frac{9}{2} = 4.5\) boxes, which means only 4 whole boxes fit along this dimension.
• In the 9 ft width, you can fit 4 whole boxes.
• In the 9 ft height, you can fit 4 whole boxes.

Therefore, the total number of boxes that fit is:

\(4×4×4=64\ boxes\)

The most likely weight of pencil is 25 g, because a pencil is a lighter object which is measured in grams.

Use the relation 1 teaspoon=4.93 mL to change 2.5 teaspoons to mL. Using the dimension analysis, the amount in mL is found as:

The percent equivalent of a fraction is obtained by multiplying the by frication by 100%.

Convert 5 ¼ into improper faction as follows

So, the percent equivalent is:

The dimension of the field is shown below.

Area of rectangle = length * width

Area of rectangle = 100 m *75 m = 7500 m2

Area of the rectangle in hectares =