Which of the following is the length of the unknown leg of a right triangle that has one leg length of 9 feet and a hypotenuse of 19 feet? (Round to the nearest tenth.)

 

Before we compare the values of the options, we convert the decimals to fractions.

5.4 becomes 54/10

6.25 becomes 625/100

Thus, the set of fractions is 11/2, 54/10, 13/3, 625/100. The least common denominator for 2, 10, 3, and 100 is 300, which we use to compare each options given.

11/2*300=1650

54/10*300=1620

13/3*300=1300

625/100*300=1875

From the above, 1875 is the greatest value which corresponds to 6.25. Therefore, 6.25 is the greatest value of all the choices given.

The interconversion of yards to feet utilizes the relationship 1 yard =3 feet. Then, 9 yards to ft becomes

                                        t

There, 9 yards is equal to 27 ft.

: We need to find the total rainfall for the months of May, June, and July using the given graph.

In the month of May, rainfall is between 3 and 4, which is halfway. Therefore, rainfall in May is 3.5 inches

On June, rainfall was 3 inch and on July the rainfall was 2.5 inches. Thus,

Total rainfall=3.5 inches+3 inches+ 2.5 inches=9.0 inches

We follow the order operations to solve for the unknown value of x.

3(2x+5)=11x+5

Open the bracket on the LHS by multiplying each term by 3

(3*2x)+(3*5)=11x+5

6x+15=11x+5

Subtract 15 from both sides

6x+15-15=11x+5-15

6x=11x-10

Subtract 11x on both sides

6x-11x=11x-11x-10

-5x=-10

Divide both sides by -5

-5x/-5=-10/-5

x= 2

Thus, the value of unknown value of x is 2.

we are asked to find the largest value from the options given. To solve this problem, we need to convert all the given values into fraction. Then find the least common denominator for all fractions, which we will use to multiply each fraction and make a comparison.

43÷55=43/55

5/7

0.729=729/1000

73%=73/100

Now, we need to find the least common denominator of 55, 7, 1000, and 100, which is 77000. We multiply each fraction by 77000 as follows:

43/55*77000=60200

5/7*77000=55000

729/1000*77000=56133

73/100*77000=56210

From the calculated values, it can be noted that 43/55 is the greatest value among the given options.

We need to find how many mL are in 5.5 teaspoons. We are told that 1 teaspoon is about 4.93 mL, which we interpret as follows:

Or

Since we are looking for mL, we use the second option.

Thus, 5.5 teaspoons can hold approximately 27 mL.

Here we need to find the actual values of the additions and see the trend the student will use to estimate the given problem. The exact sum is as follows

35+192=227

258+350=608

947+1032=1979

From the above calculations, it is evident that the student rounds up or down the ones place values. So, in the problem we need to approximate 694+7618.

694+7618=8312

We can approximate 8312 based on the provided choices is 8310.

To solve this problem, first find the radius of the circle.

We are needed to find the amount Jacob will be left with after spending and reinvesting the rest using the given information.

Amount Jacob spends=87% of $100=87/100*100=$87

Amount left to invest=$(100-87)=$13

Jacob is left with $13, which she invests and earns a profit of 75%.

Profit earned on invested amount=75% of $13=75/100*13=$9.75

So, Jacob will have $13+$9.75=$22.75

 we are to find the selling price of the sweater from the marked price and the discount. The marked price is given as

Discount=mark off rate*original price

Discount=15%*$78

Convert 15% into a fraction, which become 15/100=0.15. Then

Discount=0.15*$78=$11.70

The selling price of the sweater will be the original price less the discount or mark off value. Then,

Thus, the approximate selling price of the sweater is $66.