Using the table below, which of the following statements describes the relationship between days and dollars?  

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous data. While a bar graph does just fine even with discrete data.

We need to perform a series of numerical dimensional analysis to find the number of bags sugar needed for 300 people.

We are told that 50 people need 4 cups of sugar. This can be interpretated as:

Or

Also, one bag of sugar contains 6 cups. This can also be presented as:

Or

We use the second option relating number of people and cups, and second option relating cups of sugar and bag of sugar to find for number of bags of sugar needed for 300 people.

Therefore, 300 people will need 4 bags of sugar.

The mean is the total divided by the number of elements in the data set. From the given data set:

Total=30+29+28+30+24+12+26+33+25+23=260

Number of items, N=10

Mean=total/N=260/10=26

The mean is 26.

all products represent 100%. Then, the portion of defect products is:

0.0025 of 100%

‘of’ means multiply

0.0025 *100%=0.25%

In this problem, we take the triangle as a right-angled triangle and label it as follows:

From the Pythagoras theorem A2 + B2= C2, we can look for a combination of A and B that when the squares of A and B are summed give a square of 13.  Mathematically,

But C=13 inches

If we take A=5 inches and B=12 inches, then

Next, we take A=2.5 inches, B=6 inches

Next, we take A=2.5 inches, B=4 inches

6.25+16=169

22.25≠169

Taking A=5 inches and B=8 inches

From the above computation, the combination of A=5 inches and B=12 inches give a triangle with a hypothenuse of 13 inches.

Here we collect like terms together and solve for the unknown value of x.

7x-6=3x-26

Add 6 to both sides of the equation

7x-6+6=3x-26+6

7x=3x-20

Subtract 3x from both sides of the equation

7x-3x=-20

4x=-20

Divide both sides by 4

4x/-4=-20/4

x = -5

The value of x = -5

The median temperature can be found by organizing the temperature values from the smallest to the largest value as follows:

98.6, 98.7, 99.0, 99.0,99.2, 99.3, 99.7, 100.0

(for an even set of numbers, Median = frac{(frac{n}{2})th observation + (frac{n}{2} + 1) th observation}{2})

From the data set above, there are 8temperature values. The median is the temperature value in the middle position, which falls between the(frac{n}{2} th)and((frac{n}{2} + 1) th) position. Here N=8and median is found as:

(frac{(frac{n}{2})th + (frac{n}{2} + 1) th}{2} = )(frac{(frac{8}{2})th + (frac{8}{2} + 1) th }{2} = 4.5th position)

The element in the 4.5th position is the average of the 4th and 5th element.

(frac{99.0 + 99.2}{2} = 99.1)

Thus 99.1 is the median temperature.

we use the US customary system of units’ equivalent to convert from yards to inches. We know that 1yard=3 ft, and 1 ft =12 inches.

First, convert 2 ¾ into an improper fraction.

Then,

We are given that 1 teaspoon=4.93 mL, we can interpret it as:

Or

Since we are to find the amount in mL, we look for an option that will cancel teaspoon and remain with mL. The second option is the required conversion, and we proceed as follows:

Therefore, 2.5 teaspoons hold about 12.325 mL.

Percentages always add up to 100%. If we let x be the percent of graduates working for jobs unrelated to law, then

74%+3%+2%+x=100%

79%+x=100%

Subtract 79% from both sides of the equation

79%-79%+x=100%

x=100%-79%

x=21%

So, the number of graduates working for jobs unrelated to law is 21%.