A nurse is caring for the client.
Temperature
Hgb
Heart rate
Fundal height
Correct Answer : A,C,D,E,F
Rationale:
A. Temperature: The client's temperature decreased from 38.6°C (101.5°F) to 37.1°C (98.9°F), indicating that the febrile response to infection has resolved. This trend supports the effectiveness of the antibiotic therapy initiated on postpartum day 3.
B. Hgb: Hemoglobin dropped from 11.1 to 10 g/dL, which may reflect continued postpartum blood loss or hemodilution. This decline does not indicate improvement and may require monitoring for worsening anemia.
C. Heart rate; Heart rate improved from 110/min to 78/min, demonstrating reduced physiologic stress and better cardiovascular stability. This aligns with the drop in temperature and suggests systemic recovery from infection.
D. Fundal height; The fundus decreased from 1 cm above the umbilicus to 4 cm below, showing normal postpartum involution. A firm, midline uterus without excessive tenderness also supports clinical improvement.
E. Lochia: Lochia changed from moderate, dark brown, and foul-smelling to a small amount of brownish-red with no odor, which suggests resolving endometrial infection. This progression is typical in healthy postpartum recovery.
F. WBC count: The WBC count normalized from 33,000/mm³ to 10,000/mm³, reflecting resolution of systemic inflammation or infection. This is consistent with decreasing temperature and improved vital signs.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is D
Explanation
Rationale:
A. 42: A BMI of 42 falls in the category of class III (severe) obesity. This would only occur if the client's weight were significantly higher than 75 kg for a height of 1.8 m.
B. 28: A BMI of 28 indicates overweight status. At 75 kg and 1.8 m tall, the client does not meet the weight requirement for a BMI this high, as 28 would correspond to a weight closer to 91 kg.
C. 32: A BMI of 32 falls in the obesity range. For someone who is 1.8 m tall, a BMI of 32 would require a weight of about 104 kg, which is much higher than the client’s actual weight of 75 kg.
D. 24: The BMI is calculated as weight (kg) divided by height (m²). Using the formula:
BMI = 75 / (1.8 × 1.8) = 75 / 3.24 ≈ 23.15, which rounds to 24, placing the client in the normal weight range.
Correct Answer is D
Explanation
Rationale:
A. Raise the head of the bed when transferring a client from a bed to a stretcher: Raising the head of the bed alters body mechanics and may complicate the transfer by increasing the angle of elevation, which can lead to strain or improper alignment during the move.
B. Use a pillow underneath the client's head when repositioning a client in bed: A pillow can aid in comfort but does not contribute to safe body mechanics during repositioning. It may also interfere with alignment or reduce the ability to properly lift or turn the client.
C. Transfer on the client's weaker side when moving a client from a bed to a chair: Transferring toward the weaker side increases the risk of instability and falls. Safe ergonomic practice involves moving clients toward their stronger side to encourage participation and minimize staff effort.
D. Use a lateral transfer device when moving a client from a bed to a stretcher: Lateral transfer devices reduce friction between surfaces, making it easier to move the client without excessive force. This protects both the client and the nurse from musculoskeletal injuries and supports safe practice.
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