A nurse is assessing a client who is 6 hr postpartum and has endometritis. Which of the following findings should the nurse expect?
Temperature 37.4°C (99.3°F).
Uterine tenderness.
WBC Count 9,000/mm.
Scant lochia.
The Correct Answer is B
Choice A rationale:
A postpartum temperature of 37.4°C (99.3°F) is within the normal range. Mild temperature elevations can be expected in the immediate postpartum period without indicating infection.
Choice B rationale:
Uterine tenderness is a common finding in endometritis, which is an inflammation or infection of the inner lining of the uterus. The condition can cause pelvic pain and uterine tenderness.
Choice C rationale:
A white blood cell (WBC) count of 9,000/mm³ falls within the normal range for a postpartum client. In endometritis, an elevated WBC count would be expected due to the infection.
Choice D rationale:
Scant lochia (minimal vaginal discharge after childbirth) is a normal finding in the postpartum period and is not associated with endometritis. In endometritis, the lochia may be increased and foul-smelling.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
Choice A rationale:
Determining gestational age in the first trimester is a common and important use of ultrasound. It helps confirm the estimated due date and monitor the fetus's growth and development.
Choice B rationale:
Performing a biophysical profile in the first trimester is not a common use of ultrasound. Biophysical profiles are usually performed in the second or third trimester to assess fetal well-being.
Choice C rationale:
Observing placental maturity in the first trimester is not a standard use of ultrasound. Placental maturity is typically assessed later in pregnancy, especially in the third trimester.
Choice D rationale:
Detecting intrauterine growth restriction in the first trimester is not a primary use of ultrasound. Intrauterine growth restriction is more commonly assessed in the later stages of pregnancy when fetal growth is a concern.
Correct Answer is C
Explanation
The correct answer is Choice C.
Choice A rationale: Thiazide diuretics cause potassium and chloride loss, leading to metabolic alkalosis, not respiratory alkalosis. Hypokalemia decreases hydrogen ion excretion, increasing bicarbonate levels. Metabolic alkalosis is characterized by pH >7.45 and HCO₃⁻ >26 mEq/L rather than decreased PaCO₂.
Choice B rationale: Vomiting leads to metabolic alkalosis due to gastric acid loss. Hydrogen ion depletion increases bicarbonate concentration, shifting pH above normal. Arterial blood gases typically show increased HCO₃⁻ (>26 mEq/L) with a compensatory increase in PaCO₂ (>45 mmHg), not respiratory alkalosis.
Choice C rationale: Salicylate intoxication initially induces hyperventilation, reducing PaCO₂ levels below 35 mmHg and increasing pH above 7.45, leading to respiratory alkalosis. As toxicity progresses, metabolic acidosis may develop due to lactic acid accumulation, but early stages primarily present with respiratory alkalosis.
Choice D rationale: Hypoventilation leads to CO₂ retention, increasing PaCO₂ above 45 mmHg, forming carbonic acid (H₂CO₃) and causing respiratory acidosis. Blood gases show pH <7.35 with elevated PaCO₂, not respiratory alkalosis, which is caused by excessive CO₂ elimination through hyperventilation.
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