A nurse is caring for a client who might have a hydatidiform mole. The nurse should monitor the client for which of the following findings?
Excessive uterine enlargement.
Rapidly dropping human chorionic gonadotropin (hCG) levels.
Fetal heart rate irregularities.
Whitish vaginal discharge.
The Correct Answer is A
Choice A rationale:
Excessive uterine enlargement. Rationale: The nurse should monitor the client for excessive uterine enlargement, as a hydatidiform mole is a rare condition in pregnancy where abnormal placental tissue forms instead of a fetus. This abnormal growth can lead to uterine enlargement beyond the expected size for gestational age.
Choice B rationale:
Rapidly dropping human chorionic gonadotropin (hCG) levels. Rationale: The nurse should also monitor the client's hCG levels. In a normal pregnancy, hCG levels typically rise steadily during the early stages. However, in the case of a hydatidiform mole, hCG levels may either plateau or drop rapidly due to the abnormal placental growth.
Choice C rationale:
Fetal heart rate irregularities. Rationale: Although a hydatidiform mole does not involve a viable fetus, the nurse should still assess for fetal heart rate irregularities. In some rare cases, the presence of abnormal placental tissue can cause confusion in the diagnosis, and there may be coexisting fetal development. Fetal heart rate irregularities may indicate potential complications.
Choice D rationale:
Whitish vaginal discharge. Rationale: Whitish vaginal discharge is not typically associated with a hydatidiform mole. Instead, this finding is more commonly seen in other vaginal infections or conditions unrelated to a molar pregnancy. The nurse should be cautious not to misinterpret this symptom as a definitive sign of a hydatidiform mole.
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Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
Choice A rationale :
Scrambled eggs. Taking ferrous sulfate with scrambled eggs is not the optimal choice because eggs contain phytates, which can bind to iron and reduce its absorption. Therefore, it may hinder the effectiveness of the iron supplement, and the client may not receive the full benefit of the medication.
Choice B rationale
A high-fibre meal. While fiber is generally beneficial for digestion and overall health, it is not the best choice to take with ferrous sulfate. Fiber can also interfere with iron absorption in the same way as phytates, potentially reducing the medication's effectiveness.
Choice C rationale
Orange juice. The nurse should instruct the client to take the ferrous sulfate with orange juice. Orange juice is an excellent choice because it is rich in vitamin C. Vitamin C enhances the absorption of non-heme iron (the type of iron found in plant-based sources like ferrous sulfate). By taking the medication with orange juice, the client can maximize the absorption of iron and improve the treatment of iron-deficiency anaemia.
Choice D rationale
Milk. Consuming ferrous sulfate with milk is not advisable. Calcium, present in milk, can inhibit the absorption of iron. Therefore, taking the medication with milk might reduce the efficacy of the iron supplement and not provide the desired therapeutic effect.
Correct Answer is C
Explanation
Choice A rationale:
This statement is incorrect because Rho(D) immune globulin does not destroy Rh antibodies in a newborn who is Rh-positive. Instead, it acts to prevent the development of Rh antibodies in the mother.
Choice B rationale:
This statement is also incorrect. Rho(D) immune globulin does not destroy Rh antibodies in a woman who is Rh-negative. It is given to Rh-negative women to prevent them from forming Rh antibodies in response to Rh-positive fetal blood during pregnancy.
Choice C rationale:
This is the correct choice. Rho(D) immune globulin is given to Rh-negative women to prevent the formation of Rh antibodies. If an Rh-negative woman is exposed to Rh-positive blood (usually during childbirth), her immune system may recognize the Rh antigen as foreign and start producing Rh antibodies. These antibodies could potentially cross the placenta during a subsequent pregnancy and attack the red blood cells of an Rh-positive fetus, causing hemolytic disease in the newborn. Rho(D) immune globulin helps prevent this sensitization process.
Choice D rationale:
This statement is incorrect. Rho(D) immune globulin does not prevent the formation of Rh antibodies in a newborn who is Rh-positive. Its main purpose is to protect Rh-negative women from forming antibodies that could harm future Rh-positive pregnancies.
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