A nurse is conducting a lung assessment on a client suspected of having pneumonia. Which finding should the nurse report to the physician immediately?
Asymmetrical chest expansion
Breath sounds equal bilaterally
Bilateral symmetric vocal fremitus
Chest symmetrical
The Correct Answer is A
During a lung assessment on a client suspected of having pneumonia, the nurse should report asymmetrical chest expansion to the physician immediately. Asymmetrical chest expansion can be a sign of a serious lung condition such as pneumonia. The other options (Breath sounds equal bilaterally, Bilateral symmetric vocal fremitus, and Chest symmetrical) are normal findings and do not need to be reported immediately.
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Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
In the absence of an advance directive, the nurse should call a code ³. This means initiating emergency resuscitation measures to try to revive the client. The other options (Call a partial code, Call the physician, and Call a "slow code") are not appropriate in this situation.
Correct Answer is C
Explanation
The Agent-Host-Environment Model is a model of health promotion and illness prevention that focuses on the interaction between an infectious agent, the host (the person who is infected), and the environment in which the infection occurs. In this case, the agent is Clostridium difficile, the host is the elderly resident, and the environment is the long-term care facility where the outbreak occurred. The prescription of metronidazole (Flagyl) by the resident's primary care provider is an example of an intervention ai
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