A nurse is preparing to administer a 2 mg IV bolus of morphine sulfate. Morphine sulfate is available in a concentration of 10 mg/mL. How many mL should the nurse administer per dose? (Round the answer to the nearest tenth. Use a leading zero if it applies. Do not use a trailing zero.)
The Correct Answer is ["0.2"]
- Step 1: Identify the required dose in milligrams (mg). The nurse is scheduled to administer 2 mg of morphine sulfate.
- Step 2: Identify the concentration of the available solution. The available solution contains 10 mg of morphine sulfate per 1 mL.
- Step 3: Calculate the volume of solution needed to deliver the required dose. We can set up a proportion to solve for this:
- 10 mg is to 1 mL as 2 mg is to X mL.
- In other words, 10 mg : 1 mL = 2 mg : X mL.
- Step 4: Solve for X using cross-multiplication and division:
- Cross-multiplication gives us: 10 mg × X mL = 2 mg × 1 mL.
- Simplifying this gives us: 10X = 2.
- Dividing both sides by 10 gives us: X = 2 ÷ 10.
- Calculating the division gives us: X = 0.2.
So, the nurse should administer 0.2 mL of the morphine sulfate solution per dose.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["A","B","C","E"]
Explanation
Choice A reason: Hypoxemia, or low oxygen levels in the blood, is a primary indicator of ARF as the lungs are unable to adequately oxygenate the blood.
Choice B reason: Confusion can result from hypoxemia or hypercapnia (high carbon dioxide levels) as the brain is sensitive to changes in blood gas levels.
Choice C reason: Dyspnea, or difficulty breathing, is a hallmark symptom of ARF as the lungs struggle to maintain adequate gas exchange.
Choice D reason: Bradycardia, or a slow heart rate, is not typically associated with ARF. Tachycardia, or a fast heart rate, is more common as the body attempts to compensate for hypoxemia.
Choice E reason: Hypocarbia, or low carbon dioxide levels, can occur in ARF if the body is attempting to compensate for hypoxemia by hyperventilating.
Correct Answer is B
Explanation
Choice A reason: A BUN level of 8 mg/dL and creatinine level of 0.7 mg/dL are within normal ranges and would not be expected in a client with CKD².
Choice B reason: Elevated BUN and creatinine levels, such as 45 mg/dL and 8 mg/dL respectively, are indicative of impaired kidney function, which is consistent with CKD².
Choice C reason: A BUN level of 10 mg/dL and creatinine level of 0.3 mg/dL are lower than the expected values for a client with CKD, indicating better kidney function than typically seen in CKD².
Choice D reason: A BUN level of 23 mg/dL and creatinine level of 1.0 mg/dL may be slightly elevated but are not as indicative of CKD as the values in choice B².
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