A patient’s umbilical cord prolapses during labor.
The nurse should place her in which position? (Select all that apply.).
Knee-chest
Trendelenburg
Supine with a rolled towel under one hip
Lithotomy
Sims
Correct Answer : A,B
The correct answer is choice A and B. The nurse should place the patient in knee-chest or Trendelenburg position to relieve the pressure of the fetal presenting part on the prolapsed cord and improve fetal oxygenation. These positions also allow gravity to help keep the cord in the uterus and prevent further descent.
Choice C is wrong because supine position can worsen cord compression and compromise fetal blood flow. Choice D is wrong because lithotomy position can also increase cord descent and reduce fetal perfusion. Choice E is wrong because Sims position can cause cord prolapse if the membranes are intact or rupture spontaneously.
Normal ranges for fetal heart rate are 110 to 160 beats per minute. Cord prolapse can cause fetal bradycardia with decelerations during contractions due to cord compression.
This is a sign of fetal distress and requires immediate intervention.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
This is a condition where there is too little amniotic fluid around the fetus.This increases the risk of umbilical cord prolapse because the cord can easily slip past the presenting part of the fetus and into the cervix or vagina.
This can cause fetal hypoxia and distress due to compression or occlusion of the cord.
Choice A. Transverse lie is wrong because this is a condition where the fetus lies horizontally across the uterus.This can increase the risk of cord prolapse if the membranes rupture and the cord descends alongside or before the fetus.
Choice B. Macrosomia is wrong because this is a condition where the fetus is larger than average.This can decrease the risk of cord prolapse because the presenting part of the fetus is more likely to fill the pelvis and prevent the cord from slipping past.
Choice D. Placenta previa is wrong because this is a condition where the placenta covers part or all of the cervix.This can increase the risk of bleeding during labor, but not necessarily cord prolapse.
Correct Answer is C
Explanation
The correct answer is choice C. A client who has oligohydramnios.
Oligohydramnios is a condition where there is too little amniotic fluid around the fetus.This can cause the umbilical cord to slip down into the cervix or vagina before the baby, resulting in cord prolapse.
Cord prolapse can cut off the blood and oxygen supply to the baby and cause fetal distress or death.
Choice A is wrong because a client who is pregnant with twins is not at greater risk for cord prolapse unless there is also malpresentation of the fetuses, such as breech or transverse lie.
Choice B is wrong because a client who has gestational hypertension is not at greater risk for cord prolapse unless there is also polyhydramnios, which is excessive amniotic fluid around the fetus.
Choice D is wrong because a client who has placenta previa is not at greater risk for cord prolapse unless there is also artificial rupture of membranes by doctors.
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