A nurse is preparing to administer milrinone 50 mcg/kg IV loading dose to a client who weighs 154 lb. Available is milrinone 1 mg/mL. How many mL should the nurse administer?
(Round the answer to the nearest tenth. Use a leading zero if it applies. Do not use a trailing zero.)
The Correct Answer is ["3.5"]
To convert pounds to kilograms, divide by 2.2: 154 lb / 2.2 = 70 kg. Then multiply by the dosage per kilogram: 70 kg x 50 mcg/kg = 3500 mcg. Next, convert micrograms to milligrams by dividing by 1000: 3500 mcg / 1000 = 3.5 mg. Finally, use the formula D/H x Q to find the volume to administer, where D is the dose, H is the strength of the solution, and Q is the quantity of the solution. Plug in the values: 3.5 mg / 1 mg/mL x 1 mL = 3.5 mL. Round to the nearest tenth: 3.5 mL. Therefore, the nurse should administer 3.5 mL of milrinone.
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Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["1"]
Explanation
To answer this question, you need to convert the dosage of fentanyl from micrograms (mcg) to milligrams (mg). One milligram is equal to 1000 micrograms, so 50 mcg is equal to 0.05 mg. Then, you need to use the formula D/H x Q, where D is the desired dose, H is the dose on hand, and Q is the quantity. In this case, D is 0.05 mg, H is 0.05 mg/mL, and Q is the volume in milliliters. Plugging these values into the formula, you get:
0.05 mg / 0.05 mg/mL x Q
Q = 1 mL
Therefore, the nurse should administer 1 mL of fentanyl per dose.
Correct Answer is ["1.9"]
Explanation
To calculate the dose of dexamethasone, we need to convert the client's weight from pounds to kilograms. One pound is equal to 0.454 kg, so 132 lb is equal to 132 x 0.454 = 59.928 kg. The prescribed dose is 0.5 mg/kg/day, so the daily dose is 0.5 x 59.928 = 29.964 mg. This dose is divided equally every 6 hours, so the dose per administration is 29.964 / 4 = 7.491 mg. The concentration of the drug is 4 mg/mL, so the volume per administration is 7.491 / 4 = 1.873 mL. Rounded to the nearest tenth, the nurse should administer 1.9 mL per dose.
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