The nurse is reviewing the arterial blood gas (ABG) result for a client currently on a 100% non-rebreather mask. The nurse is able to interpret which of the following results as hypoxemic respiratory failure?

Table 9.9 Normal Arterial Blood Gas Values

ABG Value.                                                             Normal Value

pH                                                                             7.35-7.45

PaCO2                                                                                                            35-45 mmHg

HCO3-                                                                         22-26mEq/L

Base excess                                                               -2 to +2

PaO2                                                                            80-95 mmHg

SaO2                                                                            >95%

pH 7,44; Pa02 44 mmHg: PaCO2 35 mmHg; HCO3 25 mEq/L; 02 Sat 76%

pH 7.30; Pa02 80 mmHg; PaCO2 62 mmHg; HCO3 25 mEq/L; 02 Sat 94%

pH 7.35; Pa02 65 mmHg; PaCO2 40 mmHg: HCO3 26 mEq/L; 02 Sat 90%

PH 7.48; Pa02 75 mmHg; PaCO2 41 mmHg: HCO3 28 mEg/L; 02 Sat 9386

Answer and Explanation

The Correct Answer is A

A. pH 7.44; PaO2 44 mmHg; PaCO2 35 mmHg; HCO3 25 mEq/L; O2 Sat 76%: This set of arterial blood gas (ABG) values is consistent with hypoxemic respiratory failure. Hypoxemic respiratory failure is characterized by a PaO2 less than 60 mmHg, and this client has a PaO2 of 44 mmHg, which is significantly below the normal range of 80-95 mmHg. Despite the fact that the client is on a 100% non-rebreather mask (which should ideally deliver high levels of oxygen), the low PaO2 suggests that oxygenation is not being effectively improved. Additionally, the low O2 saturation of 76% further supports the diagnosis of hypoxemic respiratory failure.

B. pH 7.30; PaO2 80 mmHg; PaCO2 62 mmHg; HCO3 25 mEq/L; O2 Sat 94%: This ABG indicates respiratory acidosis (pH is low, PaCO2 is elevated), but the PaO2 of 80 mmHg is within the normal range, and the O2 saturation of 94% is also normal. Respiratory acidosis with a normal PaO2 would indicate an issue with ventilation (hypoventilation), not hypoxemic respiratory failure. The patient is retaining CO2 but is still oxygenating well, so this result does not indicate hypoxemic respiratory failure.

C. pH 7.35; PaO2 65 mmHg; PaCO2 40 mmHg; HCO3 26 mEq/L; O2 Sat 90%: This result shows a PaO2 of 65 mmHg, which is mildly low but not sufficiently low to meet the criteria for hypoxemic respiratory failure (PaO2 should be below 60 mmHg for this diagnosis). The O2 saturation of 90% is also slightly low but not critically low. This client may have mild hypoxia but is not in respiratory failure based on these values.

D. pH 7.48; PaO2 75 mmHg; PaCO2 41 mmHg; HCO3 28 mEq/L; O2 Sat 93%: In this case, the PaO2 of 75 mmHg is slightly low but still within an acceptable range, and the O2 saturation of 93% is adequate. The elevated pH and normal PaCO2 suggest the presence of respiratory alkalosis (likely caused by hyperventilation). These ABG results are not consistent with hypoxemic respiratory failure, as the oxygen levels are still within a safe range.

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Correct Answer is ["3.9"]

Explanation

Step-by-Step Solution:

Convert the toddler's weight from pounds to kilograms.

1 pound is =0.453592 kilograms.

So, 26 pounds = 26 x 0.453592 = 11.793592 kilograms.

Calculate the total daily dose of prednisolone.

The prescribed dose is 2 mg/kg/day.

The toddler weighs 11.793592 kg.

The total daily dose = 2 mg/kg/day x 11.793592 kg = 23.587184 mg/day.

Determine the dose per administration.

The total daily dose is divided into two equal doses (every 12 hours).

The dose per administration = 23.587184 mg/day / 2 = 11.793592 mg per dose.

Calculate the volume of prednisolone syrup to administer.

The available prednisolone syrup is 15 mg/5 ml.

We need to administer 11.793592 mg per dose.

To find the volume, we can set up a proportion:

15 mg / 5 ml = 11.793592 mg / x ml

Cross-multiplying:

15x = 5 x 11.793592

Solving for x:

x = (5 x 11.793592) / 15 = 3.931197 ml

Round the answer to the nearest tenth.

3.9 ml.

A. pH 7.36, Pa02 98 mmHg, PaCO2 27 mmHg, HCO3 16 mEq/L, 02 sat 99% B. pH 7.47, Pa02 91 mmHg, PaCO2 52 mmHg. HCO3 30 mEg/L, 02 sat 96% C. pH 7.45, P302 86 mmHg, PaCO2 56 mmHg, HCO3 28 mEg/L, 02 sat 94% D. PH 7.32, PaO2 88 mmHg. PaCO2 54 mmHg. HCO3 29 mEq/L. 02 sat 94%

Correct Answer is A

Explanation

A. pH 7.36, PaO2 98 mmHg, PaCO2 27 mmHg, HCO3 16 mEq/L, O2 sat 99%: This set of ABG results is consistent with fully compensated metabolic acidosis. pH 7.36: This is within the normal range (7.35-7.45), indicating that compensation has occurred, as the pH has returned to normal levels. PaCO2 27 mmHg: The PaCO2 is low, suggesting that the respiratory system has compensated for the metabolic acidosis by increasing ventilation to excrete CO2, thus reducing the acid load. HCO3 16 mEq/L: The bicarbonate level is low, which is consistent with metabolic acidosis as the primary disturbance. The PaO2 and O2 saturation are normal, indicating adequate oxygenation. Since the pH is within the normal range and the PaCO2 and HCO3 levels reflect the compensatory changes needed to correct the metabolic acidosis, this is a case of fully compensated metabolic acidosis.

B. pH 7.47, PaO2 91 mmHg, PaCO2 52 mmHg, HCO3 30 mEq/L, O2 sat 96%:

This result indicates alkalosis rather than acidosis. The pH is alkalotic (7.47), and PaCO2 is elevated (52 mmHg), which suggests respiratory acidosis as the primary disturbance. The HCO3 is also high (30 mEq/L), which is consistent with metabolic compensation for respiratory acidosis, not for metabolic acidosis. Therefore, this is not consistent with fully compensated metabolic acidosis.

C. pH 7.45, PaO2 86 mmHg, PaCO2 56 mmHg, HCO3 28 mEq/L, O2 sat 94%:

The pH is normal, but PaCO2 is elevated (56 mmHg), indicating respiratory acidosis rather than metabolic acidosis. The HCO3 is also elevated (28 mEq/L), which is consistent with compensation for respiratory acidosis, not metabolic acidosis. This result suggests respiratory acidosis with compensated metabolic alkalosis rather than metabolic acidosis.

D. pH 7.32, PaO2 88 mmHg, PaCO2 54 mmHg, HCO3 29 mEq/L, O2 sat 94%:

The pH of 7.32 indicates acidosis, but it is not within the normal range, so this is not fully compensated. The PaCO2 is elevated (54 mmHg), indicating respiratory acidosis, and the HCO3 is elevated (29 mEq/L), showing metabolic compensation. However, since the pH has not yet returned to normal (it remains acidotic), this is an example of partially compensated respiratory acidosis, not fully compensated metabolic acidosis.

respiratory acidosis, not fully compensated metabolic acidosis.

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Explanation

Correct Answer is A

Explanation

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