What is the most common cause of subinvolution?
Retained placental fragments
Infection
Uterine fibroids
Multiparity
The Correct Answer is A
The correct answer is choice A. Retained placental fragments are the most common cause of subinvolution. Subinvolution is a condition where the uterus does not return to its normal size after childbirth. Retained placental fragments prevent the uterus from contracting properly and cause prolonged bleeding and infection.
Choice B is wrong because infection is not the most common cause of subinvolution, but it can be an aggravating factor. Infection can cause inflammation and interfere with the healing of the uterine lining.
Choice C is wrong because uterine fibroids are not the most common cause of subinvolution, but they can be a predisposing factor. Uterine fibroids are benign tumors that can distort the shape of the uterus and impair its contraction.
Choice D is wrong because multiparity is not the most common cause of subinvolution, but it can be a predisposing factor. Multiparity means having given birth more than once, which can weaken the uterine muscles and reduce their ability to contract.
Normal ranges for uterine involution are as follows:
• Uterus weight: decreases from about 1000 g at delivery to about 60 g at six weeks postpartum.
• Uterus height: decreases from about 20 cm above the pubic bone at delivery to about 12 cm at one week postpartum, and then descends into the pelvis by six weeks postpartum.
• Uterus size: decreases from about 20 times its normal size at delivery to about its normal size at six weeks postpartum.
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Related Questions
Correct Answer is B
Explanation
A client who had a vertical incision on her uterus but a low transverse incision on her skin for her previous cesarean delivery has the highest risk of uterine rupture during labor.This is because a vertical incision on the uterus weakens the uterine wall and increases the risk of rupture during contractions.
Normal ranges for uterine rupture during labor are 0.2% to 1.5% for women who have had one previous cesarean delivery with a low transverse incision and 0.9% to 3.7% for women who have had two or more previous cesarean deliveries with low transverse incisions.
Correct Answer is D
Explanation
The correct answer is choice D. To stabilize the lower uterine segment.Palpating the uterus after delivery helps to determine its size, firmness and rate of descent, which are indicators of its involution.The nurse places one hand just above the symphysis pubis to support the lower uterine segment and prevent it from being pushed down by the pressure of the other hand on the fundus.This prevents complications such as uterine inversion or prolapse.
Choice A is wrong because uterine prolapse is not prevented by placing one hand above the symphysis pubis, but by supporting the lower uterine segment with that hand.
Choice B is wrong because uterine hemorrhage is not prevented by placing one hand above the symphysis pubis, but by massaging the fundus to make it firm and contract the blood vessels.
Choice C is wrong because uterine inversion is not prevented by placing one hand above the symphysis pubis, but by stabilizing the lower uterine segment with that hand and avoiding excessive traction on the umbilical cord.
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