Which of the following represents the overall reaction for aerobic respiration?
C6H12O6 + 6 H20 🡪 6 CO2 + 6 02
C6H12O6 +602 🡪 6 CO2 + 6 H20
C6H12O6 +6 CO2 🡪 6 02 + 6 H20
CO2 +6 H20 🡪 C6H12O6 + 6 02
6 02+6 H20 🡪 C6H12O6 + 6 CO2
The Correct Answer is B
A. C6H12O6 + 6 H2O -> 6 CO2 + 6 O2: This equation incorrectly lists water as a reactant instead of oxygen. Aerobic catabolism requires molecular oxygen as the terminal electron acceptor in the electron transport chain. Metabolism of glucose without oxygen input prevents oxidative phosphorylation.
B. C6H12O6 + 6 O2 -> 6 CO2 + 6 H2O: Hexose oxidation involves the complete breakdown of glucose in the presence of oxygen. This metabolic pathway yields carbon dioxide and water as primary byproducts while capturing chemical energy. It accurately reflects the stoichiometric balance of aerobic cellular respiration.
C. C6H12O6 + 6 CO2 -> 6 O2 + 6 H2O: Carbon dioxide functions as a metabolic waste product rather than a reactant in human cellular respiration. Glucose does not react with carbon dioxide to produce oxygen during heterotrophic metabolism. This chemical arrangement reverses the standard physiological gas exchange.
D. CO2 + 6 H2O -> C6H12O6 + 6 O2: This formula represents the endergonic process of photosynthesis occurring in photoautotrophic organisms. It describes the fixation of inorganic carbon into organic compounds using light energy. Eukaryotic animal cells lack the chloroplasts necessary to drive this specific anabolic reaction.
E. 6 O2 + 6 H2O -> C6H12O6 + 6 CO2: The combination of oxygen and water does not spontaneously synthesize glucose molecules in biological systems. This equation fails to account for the carbon source required for carbohydrate formation. It violates the fundamental thermodynamic principles governing respiratory substrate breakdown and energy release.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
A. AB, Rh-negative: Individuals with this blood type express both A and B antigens on their erythrocyte membranes. If transfused into a recipient with type O, A, or B blood, these antigens would trigger an immediate and severe hemolytic transfusion reaction. They are considered universal recipients of cells, not universal donors.
B. AB, Rh-positive: This blood type possesses all three major antigens: A, B, and the Rh(D) factor. Consequently, these red blood cells would be attacked by the antibodies of almost any recipient lacking these specific markers. While they can receive any blood type, their cells are only compatible with other AB-positive individuals.
C. O, Rh-negative: This blood type lacks A, B, and Rh(D) surface antigens, which prevents recognition by the recipient's anti-A, anti-B, or anti-D antibodies. Because there are no antigens for the host's immune system to attack, these cells can be safely administered to any ABO group in emergencies. It is the gold standard for universal erythrocyte donation.
D. O, Rh-positive: While these cells lack A and B antigens, the presence of the Rh(D) antigen makes them incompatible for Rh-negative recipients. Transfusing Rh-positive cells into an Rh-negative individual can lead to isoimmunization and future hemolytic complications. Thus, it does not meet the criteria for a truly universal donor.
E. ABO, Rh-negative: This is not a specific clinical blood type but rather a reference to the classification systems themselves. A universal donor must have a specific phenotype within these systems, which is the absence of all primary antigens. The correct clinical designation for the universal donor of red cells is O-negative.
Correct Answer is D
Explanation
A. 6: Hemoglobin lacks the structural capacity to bind 6 oxygen molecules simultaneously. The protein is a tetramer, meaning it consists of only 4 polypeptide subunits. Each subunit is limited to the binding of a single heme group and its associated iron ion.
B. 2: This number represents only half of the potential carrying capacity of a fully saturated hemoglobin molecule. In the high partial pressure of oxygen found in pulmonary capillaries, hemoglobin typically binds more than two molecules. This would reflect a low oxygen saturation level of 50%.
C. 3: Binding 3 molecules would result in 75% oxygen saturation, which occurs as blood unloads oxygen to resting tissues. However, it does not represent the maximum theoretical or physiological limit of the transport protein. The molecular structure allows for one additional binding site to be filled.
D. 4: Each hemoglobin molecule is a tetramer composed of 4 globin chains, each containing a central heme group with a ferrous iron atom. Each iron atom can reversibly bind 1 molecule of O2. Therefore, a single hemoglobin molecule can carry a maximum of 4 oxygen molecules.
E. 5: Human hemoglobin does not possess a fifth binding site or heme group to accommodate an extra oxygen molecule. The quaternary structure is strictly limited to 4 subunits. Any value above 4 is biologically and chemically impossible for a standard adult hemoglobin A molecule.
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