What is the ABO blood type of subject 1?

Correct answer: Blood group 0
Subject 1
Subject 2
Subject 3
Subject 4
The Correct Answer is A
A. Subject 1: Because Subject 1 lacks both A and B surface antigens, the individual is classified as having blood type O. In the ABO system, type O is characterized by the absence of these specific glycoproteins. This phenotype results in the presence of both anti-A and anti-B antibodies in the plasma.
B. Subject 2: The sample demonstrates visible agglutination in the presence of Anti-A antiserum while remaining smooth in Anti-B antiserum. This indicates the presence of A antigens and the absence of B antigens on the erythrocyte membranes. Consequently, the ABO blood group for this individual is Type A.
C. Subject 3: There is a clear lack of agglutination in the Anti-A antiserum, but distinct clumping is present in the Anti-B antiserum. The reaction confirms that the red blood cells possess B antigens but lack A antigens. This specific reactivity pattern identifies the individual as having Type B blood.
D. Subject 4: Agglutination is prominently visible in both the Anti-A and Anti-B antiserum wells for this individual. This positive reaction in both tests proves the simultaneous presence of both A and B surface antigens. Therefore, Subject 4 is classified as having blood type AB.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
A. Heme does not get converted into amino acids. Instead, heme is split into iron and a porphyrin ring. The iron is stored or reused, and the porphyrin ring is converted into biliverdin and then bilirubin for excretion. This pathway is completely different from protein hydrolysis.
B. Globin: The blue box leads to a pathway labeled “hydrolyzed to free amino acids.” This describes what happens to the globin portion of hemoglobin. Globin consists of protein chains, and when red blood cells are broken down, these protein chains are hydrolyzed into individual amino acids. The body then reuses these amino acids to build new proteins or for other metabolic functions. Therefore, box 2 represents globin.
C. Erythropoietin is not part of hemoglobin structure. It is a hormone that regulates red blood cell production. It is not broken down during
Correct Answer is B
Explanation
A. C6H12O6 + 6 H2O -> 6 CO2 + 6 O2: This equation incorrectly lists water as a reactant instead of oxygen. Aerobic catabolism requires molecular oxygen as the terminal electron acceptor in the electron transport chain. Metabolism of glucose without oxygen input prevents oxidative phosphorylation.
B. C6H12O6 + 6 O2 -> 6 CO2 + 6 H2O: Hexose oxidation involves the complete breakdown of glucose in the presence of oxygen. This metabolic pathway yields carbon dioxide and water as primary byproducts while capturing chemical energy. It accurately reflects the stoichiometric balance of aerobic cellular respiration.
C. C6H12O6 + 6 CO2 -> 6 O2 + 6 H2O: Carbon dioxide functions as a metabolic waste product rather than a reactant in human cellular respiration. Glucose does not react with carbon dioxide to produce oxygen during heterotrophic metabolism. This chemical arrangement reverses the standard physiological gas exchange.
D. CO2 + 6 H2O -> C6H12O6 + 6 O2: This formula represents the endergonic process of photosynthesis occurring in photoautotrophic organisms. It describes the fixation of inorganic carbon into organic compounds using light energy. Eukaryotic animal cells lack the chloroplasts necessary to drive this specific anabolic reaction.
E. 6 O2 + 6 H2O -> C6H12O6 + 6 CO2: The combination of oxygen and water does not spontaneously synthesize glucose molecules in biological systems. This equation fails to account for the carbon source required for carbohydrate formation. It violates the fundamental thermodynamic principles governing respiratory substrate breakdown and energy release.
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