Within three days of birth, a newborn has developed a yellowish tinge that extends from the face to mid-chest is lethargic, and has to be awakened to feed. Which condition does the nurse suspect this infant is manifesting?
Physiologic jaundice
Pathologic jaundice
Breast milk jaundice
The Correct Answer is B
Pathologic jaundice. This type of jaundice occurs within the first 24 hours of birth and is caused by an underlying health condition, such as blood type incompatibility, infection, or liver problems. It can lead to serious complications, such as brain damage, if not treated promptly. Pathologic jaundice requires medical attention and often involves phototherapy or blood transfusion to lower the bilirubin levels in the baby's blood.
Choice A is not correct because physiologic jaundice is a normal and harmless condition that affects most newborns. It usually appears between the second and fourth day after birth and resolves by the second week. It is caused by the immature liver's inability to process bilirubin efficiently.
Choice C is not correct because breast milk jaundice is a rare condition that affects some breastfed babies. It usually appears after the first week of life and lasts up to a month or longer. It is caused by a substance in breast milk that interferes with the liver's ability to eliminate bilirubin.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
Asymmetrical chest movement is a sign of respiratory distress in the newborn, as it indicates unequal lung expansion or airway obstruction. A respiratory rate of 50 breaths/minute (choice B) is normal for a newborn, as is acrocyanosis (choice C), which is a bluish discoloration of the hands and feet due to immature peripheral circulation. Short periods of apnea (less than 15 seconds) (choice D) are also common and benign in newborns unless they are associated with bradycardia or cyanosis.
Choice B is not correct because a respiratory rate of 50 breaths/minute is within the normal range for a newborn.
Choice C is not correct because acrocyanosis is a normal finding in newborns and does not indicate respiratory distress.
Choice D is not correct because short periods of apnea (less than 15 seconds) are normal in newborns and do not indicate respiratory distress.
Correct Answer is A
Explanation
The baby sleeps with the mother in bed. This is because sleeping with the baby in the same bed increases the risk of sudden infant death syndrome (SIDS), suffocation, strangulation, and entrapment. The nurse should have assessed the mother’s sleeping arrangements for the baby and provided education on safe sleep practices before discharge. The nurse should advise the mother to place the baby on a firm surface, such as a crib or bassinet, in the same room but not in the same bed as the mother.
Choice B is wrong because having windows covered with screens is not a sign of inadequate home assessment. Screens can help prevent insects and other animals from entering the home and posing a health hazard.
Choice C is wrong because having a refrigerator in the kitchen is not a sign of inadequate home assessment. A refrigerator can help store food and breast milk safely and prevent spoilage and contamination.
Choice D is wrong because having a changing area for the baby is not a sign of inadequate home assessment. A changing area can help keep the baby clean and comfortable and prevent diaper rash and infection.
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