A nurse is caring for a client who has a placenta previa.
Which of the following findings should the nurse expect?
Nausea.
Polyhydramnios.
Uterine tenderness.
Spotting.
The Correct Answer is D
The correct answer is choice D, spotting.
Placenta previa is a condition where the placenta implants in the lower part of the uterus, partly or completely covering the cervical opening.
This can cause painless, bright red vaginal bleeding, usually in the third trimester.
Spotting is a sign of placenta previa and should be reported to the provider immediately.
Choice A is wrong because nausea is not a specific finding of placenta previa.
Nausea can occur in normal pregnancy or in other conditions such as hyperemesis gravidarum or preeclampsia.
Choice B is wrong because polyhydramnios is not a finding of placenta previa.
Polyhydramnios is a condition where there is too much amniotic fluid in the uterus, which can cause complications such as preterm labor, cord prolapse, or fetal malformations.
Choice C is wrong because uterine tenderness is not a finding of placenta previa.
Uterine tenderness is a sign of abruptio placentae, which is a condition where the placenta separates from the uterine wall before delivery.
This can cause severe abdominal pain, dark red vaginal bleeding, and fetal distress.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation

This is because varicella, or chickenpox, is a highly contagious disease caused by the varicellazoster virus (VZV), which can spread through the air or by direct contact with the fluid from the blisters. A negative air pressure room prevents the air from the room from circulating to other areas of the hospital, reducing the risk of transmission to other patients and staff.
Choice A is wrong because aspirin should not be given to children with chickenpox, as it can cause a serious condition called Reye’s syndrome, which affects the brain and liver. Instead, acetaminophen can be used to reduce fever.
Choice B is wrong because droplet precautions are not enough to prevent the spread of chickenpox. Droplet precautions involve wearing a mask and gloves when in close contact with the patient, but they do not prevent the virus from traveling through the air. Airborne precautions, which include a negative air pressure room and wearing a respirator, are needed for chickenpox.
Choice D is wrong because Koplik spots are not a sign of chickenpox, but of measles, another viral infection that causes a rash. Chickenpox causes an itchy rash with small, fluid-filled blisters that crust over.
Correct Answer is C
Explanation
The correct answer is choice C. A client who was just given a glass of orange juice for a low blood glucose level.
This client should be assessed first because they are at risk of hypoglycemia, which is a medical emergency that can cause seizures, coma, or death if not treated promptly.
The nurse should check the client’s blood glucose level again and provide additional carbohydrates or glucose if needed.
Choice A is wrong because a client who is scheduled for a procedure in 1 hr is not in immediate danger and can be assessed later.
The nurse should verify the client’s consent, allergies, and vital signs before the procedure, but this is not a priority over a client with low blood glucose.
Choice B is wrong because a client who received a pain medication 30 min ago for postoperative pain is likely to have improved pain relief and does not need immediate assessment.
The nurse should monitor the client’s pain level, vital signs, and respiratory status periodically, but this is not a priority over a client with low blood glucose.
Choice D is wrong because a client who has 100 mL of fluid remaining in his IV bag is not in immediate danger and can be assessed later.
The nurse should change the IV bag when it is empty or nearly empty, but this is not a priority over a client with low blood glucose.
Normal blood glucose levels are between 70 to 100 mg/dL (3.9 to 5.5 mmol/L) when fasting, and less than 140 mg/dL (7.8 mmol/L) two hours after eating. A blood glucose level below 70 mg/dL (3.9 mmol/L) is considered hypoglycemia and requires immediate treatment. Orange juice is a source of simple carbohydrates that can raise blood glucose quickly, but it may not be enough to prevent hypoglycemia in some cases.
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