A nurse is reinforcing teaching with a client about increasing her intake of fiber. Which of the following foods should the nurse encourage the client to eat?

Choice A reason: Ammonia 55 mg/dL is within the normal range of 15 to 60 mg/dL and does not indicate any liver dysfunction or bleeding risk.

Choice B reason: Bilirubin 1.0 mg/dL is within the normal range of 0.3 to 1.2 mg/dL and does not indicate any liver damage or jaundice.

Choice C reason: Aspartate aminotransferase 34 units/L is within the normal range of 10 to 40 units/L and does not indicate any liver inflammation or injury.

Choice D reason: Platelets 60,000/mm³ is below the normal range of 150,000 to 450,000/mm³ and indicates thrombocytopenia, which is a low platelet count that can increase the risk of bleeding during or after the liver biopsy. The nurse should report this value to the provider and monitor the client for signs of bleeding, such as bruising, petechiae, hematuria, or melena.

Choice A reason: Chest x-ray showing cardiomegaly is not a new finding for the client who has heart failure, as it indicates enlargement of the heart due to increased workload and pressure on the cardiac chambers.

Choice B reason: PaCO2 55 mmHg is an abnormal finding for the client who has heart failure, as it indicates respiratory acidosis, which is a condition where the lungs cannot eliminate enough carbon dioxide and the blood becomes too acidic. This can be caused by pulmonary edema, which is a complication of heart failure that impairs gas exchange and ventilation.

Choice C reason: Potassium level 4.5 mEq/L is a normal finding for the client who has heart failure, as it indicates adequate electrolyte balance and renal function.

Choice D reason: Urinary output of 1,000 mL in 12 hr is a normal finding for the client who has heart failure, as it indicates adequate fluid status and cardiac output.