A nurse is to infuse two 1L bags of normal saline to a patient at 80ml/hr. How many hours will it take to infuse the total amount of normal saline?
(Round to the whole number. Assume no interruptions in the infusion.)
The Correct Answer is ["25"]
To calculate the number of hours required to infuse two 1L bags of normal saline at a rate of 80 ml/hr, you can use the following formula:
Time (hours) = Total volume (ml) / Infusion rate (ml/hr)
First, calculate the total volume of normal saline to be infused:
Total volume = 2 bags x 1L/bag x 1000 ml/L = 2000 ml
Now, plug this into the formula:
Time (hours) = 2000 ml / 80 ml/hr
Time (hours) = 25 hours
So, it will take 25 hours to infuse the total amount of normal saline at a rate of 80 ml/hr, assuming no interruptions in the infusion. Rounded to the nearest whole number, it will take 25 hours.
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Correct Answer is A
Explanation
A. Calcium Oxalate
The most common substance found in the analysis of renal stones is calcium oxalate. Calcium oxalate stones are the most prevalent type of kidney stones, accounting for the majority of cases. These stones can form when there is an excess of calcium or oxalate in the urine, and they can vary in size and shape. Other types of kidney stones include uric acid stones, struvite stones (magnesium-ammonium phosphate), and cystine stones, but calcium oxalate stones are the most common.
Correct Answer is ["250"]
Explanation
To calculate the infusion rate, you first need to determine the total volume to be infused and the total time over which the infusion will occur.
Three 1L bags need to be infused over 12 hours.
Total volume = 3 bags * 1000 mL/bag = 3000 mL
Total time = 12 hours
Now, to find the rate in milliliters per hour (mL/h), divide the total volume by the total time:
Infusion rate = Total volume / Total time
Infusion rate = 3000 mL / 12 hours = 250 mL/h
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