A nurse assesses clients on the medical-surgical unit. Which client is at greatest risk for development of obstructive sleep apnea?
A 42-year-old man with gastroesophageal reflux disease
A 55-year-old woman who is 50 lb (23 kg) overweight
A 20-year-old woman who is 8 months pregnant
A 73-year-old man with type 2 diabetes mellitus
The Correct Answer is B
Choice A Reason:
A 42-year-old man with gastroesophageal reflux disease (GERD) is not at the highest risk for obstructive sleep apnea (OSA). While GERD can be associated with OSA, it is not a primary risk factor. The main risk factors for OSA include obesity, age, and anatomical features that can obstruct the airway. Therefore, this individual is not at the greatest risk compared to others.
Choice B Reason:
A 55-year-old woman who is 50 lb (23 kg) overweight is at significant risk for developing OSA. Obesity is one of the most critical risk factors for OSA because excess weight can lead to fat deposits around the upper airway, which can obstruct breathing during sleep. Additionally, being overweight increases the likelihood of other conditions that can exacerbate OSA, such as hypertension and metabolic syndrome.
Choice C Reason:
A 20-year-old woman who is 8 months pregnant may experience temporary sleep disturbances, including snoring and mild sleep apnea, due to hormonal changes and increased abdominal pressure. However, pregnancy-related sleep apnea is usually transient and resolves after childbirth. Therefore, while she may have an increased risk during pregnancy, it is not as significant as the risk posed by obesity.
Choice D Reason:
A 73-year-old man with type 2 diabetes mellitus has an increased risk of OSA, as diabetes is associated with obesity and metabolic syndrome, which are risk factors for OSA. However, the presence of diabetes alone does not pose as high a risk as obesity. Therefore, while this individual is at risk, it is not as high as the risk associated with being significantly overweight.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["A","C","D","E","G"]
Explanation
Choice A Reason: Adherence to proper hand hygiene
Proper hand hygiene is a fundamental practice in preventing infections, including ventilator-associated pneumonia (VAP). Hand hygiene involves washing hands with soap and water or using an alcohol-based hand sanitizer before and after patient contact, after touching potentially contaminated surfaces, and before performing any aseptic procedures. This practice helps to reduce the transmission of pathogens that can cause infections in mechanically ventilated patients. Studies have shown that adherence to hand hygiene protocols significantly decreases the incidence of VAP and other healthcare-associated infections.
Choice B Reason: Suction the client at least every 2 hours
While suctioning is an important aspect of care for mechanically ventilated patients, routine suctioning every 2 hours is not recommended. Instead, suctioning should be performed based on the patient’s clinical condition and as needed. Over-suctioning can cause trauma to the airway and increase the risk of infection. Therefore, this choice is not included in the best practices for preventing VAP.
Choice C Reason: Administering antiulcer medication
Administering antiulcer medication is a recommended practice to prevent stress ulcers and gastrointestinal bleeding in mechanically ventilated patients. Stress ulcers can lead to complications such as aspiration of gastric contents, which can contribute to the development of VAP. Antiulcer medications, such as proton pump inhibitors or H2 receptor antagonists, help to reduce gastric acidity and the risk of ulcer formation. This practice is part of the comprehensive care plan to prevent VAP.

Choice D Reason: Providing oral care per protocol
Providing oral care per protocol is a critical component of VAP prevention. Oral care involves cleaning the patient’s mouth, teeth, and gums to reduce the colonization of harmful bacteria that can be aspirated into the lungs. Protocols for oral care typically include the use of antiseptic solutions, such as chlorhexidine, to disinfect the oral cavity. Regular oral care has been shown to significantly reduce the incidence of VAP in mechanically ventilated patients.
Choice E Reason: Elevating the head of the bed
Elevating the head of the bed to an angle of 30 to 45 degrees is a recommended practice to prevent VAP. This position helps to reduce the risk of aspiration of gastric contents into the lungs, which is a major risk factor for VAP. Elevating the head of the bed also promotes better lung expansion and ventilation, which can improve the patient’s respiratory status. This practice is widely recognized as an effective measure to prevent VAP.
Choice F Reason: Suctioning the client on a regular schedule
Similar to Choice B, routine suctioning on a regular schedule is not recommended. Suctioning should be performed based on the patient’s clinical needs and not on a fixed schedule. Over-suctioning can cause harm and increase the risk of infection. Therefore, this choice is not included in the best practices for preventing VAP.
Choice G Reason: Turning and positioning the client at least every 2 hours
Turning and positioning the client at least every 2 hours is an important practice to prevent complications such as pressure ulcers and to promote lung expansion. Regular repositioning helps to improve ventilation and drainage of secretions, reducing the risk of VAP. This practice is part of the standard care for mechanically ventilated patients to prevent various complications, including VAP.
Correct Answer is A
Explanation
Choice A Reason:
0.45% sodium chloride (half-normal saline) is an appropriate solution for treating hypernatremia, especially in a client who is NPO (nothing by mouth). This hypotonic solution helps to gradually reduce the serum sodium levels by providing free water to the extracellular space, which dilutes the high sodium concentration. It is essential to administer this solution slowly to avoid rapid shifts in fluid balance, which can lead to cerebral edema.
Choice B Reason:
Dextrose 5% in 0.9% sodium chloride (D5NS) is not the best choice for treating hypernatremia. While it provides some free water, the presence of 0.9% sodium chloride makes it an isotonic solution, which does not effectively lower serum sodium levels. This solution is more suitable for maintaining fluid balance rather than correcting hypernatremia.
Choice C Reason:
Lactated Ringer’s is also not appropriate for treating hypernatremia. This isotonic solution contains electrolytes, including sodium, which can exacerbate hypernatremia rather than correct it. Lactated Ringer’s is typically used for fluid resuscitation and electrolyte replacement in other clinical scenarios.
Choice D Reason:
Dextrose 10% in water (D10W) is a hypertonic solution and is not suitable for treating hypernatremia. While it provides free water, the high concentration of dextrose can lead to rapid shifts in fluid balance and potential complications such as hyperglycemia. This solution is generally used for providing calories and preventing hypoglycemia in specific clinical situations.
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