A nurse is caring for a client who is experiencing a panic attack.
Which of the following actions should the nurse take?
Administer a dose of atomoxetine to decrease anxiety.
Encourage the client to watch television.
Teach the client how to meditate.
Sit with the client to provide a sense of security.
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The Correct Answer is D
The correct answer is choice D. Sit with the client to provide a sense of security.
A client who is experiencing a panic attack has a very high level of anxiety and a diminished ability to focus.
The nurse should stay with the client and remain calm and reassuring during the panic attack. This can help the client feel safe and supported, and reduce the intensity of the anxiety.
Choice A is wrong because atomoxetine is not an anti-anxiety medication, but a selective norepinephrine reuptake inhibitor (SNRI) used to treat attention deficit hyperactivity disorder (ADHD). It has no effect on reducing anxiety and can cause side effects such as insomnia, nausea, and increased blood pressure.
Choice B is wrong because encouraging the client to watch television is not a therapeutic intervention for a panic attack.
Watching television can increase the stimuli in the client’s environment, which can worsen the anxiety.
The nurse should maintain an environment with low stimulation for the client experiencing a panic attack. Dim lighting, few people, and minimal distractions can assist the nurse to decrease the client’s level of anxiety.
Choice C is wrong because teaching the client how to meditate is not appropriate during a panic attack.
Meditation is a relaxation technique that can be helpful for preventing or reducing anxiety, but it requires concentration and focus, which are impaired in a panic attack. The nurse should teach the client how to meditate when the client is calm and receptive, not when the client is in crisis.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
The correct answer is C. FHR baseline 170/min. This is because a normal FHR baseline is between 110 and 160 bpm, and anything above or below this range indicates fetal distress and should be reported to the provider. A FHR baseline of 170/min could indicate fetal tachycardia, which could be caused by maternal fever, infection, dehydration, fetal anemia, or fetal hypoxia.
Choice A is wrong because early decelerations in the FHR are normal and benign, and indicate head compression during contractions.
They do not require any intervention or reporting.
Choice B is wrong because contractions lasting 80 seconds are within the normal range for active labor, which is 40 to 90 seconds per contraction.
They do not indicate any complication or abnormality.
Choice D is wrong because a temperature of 37.4° C (99.3° F) is slightly elevated but not considered a fever. A fever is defined as a temperature of 38° C (100.4° F) or higher.
A mild increase in temperature could be due to dehydration, exertion, or environmental factors, and does not necessarily indicate infection or inflammation.
Correct Answer is A
Explanation
The correct answer is choice A. A client who has a hip fracture and a new onset of tachypnea.
This client has a high risk of developing a pulmonary embolism, which is a life-threatening condition that requires immediate intervention.
Tachypnea is a sign of respiratory distress and hypoxia, which can indicate a pulmonary embolism.
The nurse should assess this client first and notify the provider.
Choice B is wrong because a client who has diabetes mellitus and an HbA1c of 6.8% is wellcontrolled and does not need urgent attention.
The normal range for HbA1c is 4% to 6%, and the goal for diabetic clients is less than 7%.
Choice C is wrong because a client who has epidural analgesia and weakness in the lower extremities is expected to have some degree of motor impairment due to the medication.
The nurse should monitor the client’s sensation, movement, and pain level, but this is not a priority over choice A. Choice D is wrong because a client who has sinus arrhythmia and is receiving cardiac monitoring is not in immediate danger.
Sinus arrhythmia is a normal variation of heart rhythm that occurs with breathing.
The nurse should observe the client’s vital signs and cardiac rhythm, but this is not a priority over choice A.
The correct answer is choice A. A client who has a hip fracture and a new onset of tachypnea.
This client has a high risk of developing a pulmonary embolism, which is a life-threatening condition that requires immediate intervention.
Tachypnea is a sign of respiratory distress and hypoxia, which can indicate a pulmonary embolism.
The nurse should assess this client first and notify the provider.
Choice B is wrong because a client who has diabetes mellitus and an HbA1c of 6.8% is wellcontrolled and does not need urgent attention.
The normal range for HbA1c is 4% to 6%, and the goal for diabetic clients is less than 7%.
Choice C is wrong because a client who has epidural analgesia and weakness in the lower extremities is expected to have some degree of motor impairment due to the medication.
The nurse should monitor the client’s sensation, movement, and pain level, but this is not a priority over choice A. Choice D is wrong because a client who has sinus arrhythmia and is receiving cardiac monitoring is not in immediate danger.
Sinus arrhythmia is a normal variation of heart rhythm that occurs with breathing.
The nurse should observe the client’s vital signs and cardiac rhythm, but this is not a priority over choice A.
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