A nurse is planning care for a client who has rheumatoid arthritis. Which of the following interventions should the nurse include in the plan?
Encourage the client to take a cool sponge bath each morning.
Administer opioid analgesia.
Increase the client's dietary iron intake.
Restrict the client's intake of foods high in purines.
The Correct Answer is C
- A. Encourage the client to take a cool sponge bath each morning is not correct because it can increase joint stiffness and pain.
- B. Administer opioid analgesia is not correct because it is not the first-line treatment for rheumatoid arthritis and can cause dependence and tolerance.
- C. Increase the client's dietary iron intake is indicate in rheumatoid arthritis due to anemia of chronic inflammation.
- D. Restrict the client's intake of foods high in purines is incorrect in rheumatoid. It is an important measure in gouty arthritis.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
Choice A rationale:
Repositioning the NG tube is not the appropriate action for hyperosmolar dehydration. This condition occurs due to an excessive concentration of solutes in the body, leading to a decrease in intracellular water. Repositioning the tube would not address the hyperosmolarity issue.
Choice B rationale:
Increasing the rate of formula delivery may exacerbate the problem by introducing more concentrated formula into the client's system, worsening hyperosmolarity. This choice can lead to further dehydration and electrolyte imbalances.
Choice C rationale:
Adding water to the formula is the correct action in this scenario. Hyperosmolar dehydration requires dilution of the concentrated formula to reduce the osmolarity. By adding water to the formula, the nurse can decrease the concentration of solutes, helping to rehydrate the client effectively.
Choice D rationale:
Switching to a lactose-free formula is not the appropriate intervention for hyperosmolar dehydration. The issue lies in the concentration of the formula, not in its lactose content. Adding water is the more suitable and direct approach to address the problem.
Correct Answer is ["18"]
Explanation
The client weighs 198 lb, which is equivalent to (198 ÷ 2.2 = 90kg.
Therefore, the amount of mannitol for the test dose is 0.2 g/kg x 90 kg = 18 g. The nurse should administer 18 g of mannitol IV bolus over 5 min as a test dose to the client who has severe oliguria.
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