A nurse is teaching a patient to obtain a specimen for fecal occult blood testing using the fecal immunochemical testing (FIT) at home. How does the nurse instruct the patient to collect the specimen?
Get three fecal smears from one bowel-movement.
Collect one fecal smear from three separate bowel movements,
Obtain one fecal smear from an early morning bowel movement.
Get three fecal smears when you see blood in your bowel movement.
The Correct Answer is B
A. Get three fecal smears from one bowel movement. FIT only requires one sample per bowel movement, but it is best to test multiple separate bowel movements for accuracy.
B. Collect one fecal smear from three separate bowel movements. FIT testing detects blood proteins using antibodies, and blood presence in stool can be intermittent. Collecting samples from different days increases accuracy.
C. Obtain one fecal smear from an early morning bowel movement. Time of day does not matter, but multiple samples from different bowel movements are preferred.
D. Get three fecal smears when you see blood in your bowel movement. FIT is meant to detect hidden (occult) blood that is not visible.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
A. Continuous output from the stoma. Ileostomies typically have continuous liquid output, which is expected.
B. Presence of blood in the stool: Blood in the stool can indicate stomal irritation, ulceration, or bleeding from the intestines, which requires immediate medical attention.
C. Malodorous stool. While foul-smelling stool can suggest an issue (e.g., infection), it is not necessarily an emergency.
D. Liquid consistency with hard stool particles. Ileostomy output is expected to be liquid, and occasional solid particles may occur if certain foods are not fully digested.
Correct Answer is A
Explanation
client with a weight of 150 lb and height of 68 inches BMI=150×703/682=22.8 (Normal weight)
A client with a weight of 128 lb and height of 70 inchesBMI=128×703/70 2=18.4 (Underweight)
client with a weight of 200 lb and height of 72 inches
BMI=200×703/722=27.1 (Overweight)
client with a weight of 133 lb and a height of 60 inchesBMI=133×703/602=26 (Overweight)
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