Necrotic death of brain tissue usually produces:
Fat necrosis
Coagulative necrosis
Caseous necrosis
Liquefactive necrosis
The Correct Answer is D
Choice A Reason:
Fat necrosis occurs when fatty tissues are damaged, leading to the release of enzymes that break down fat cells. This type of necrosis is commonly seen in the pancreas and breast tissue, often due to trauma or pancreatitis. It is not typically associated with brain tissue.
Choice B Reason:
Coagulative necrosis is characterized by the preservation of the basic outline of the coagulated cells for a few days after cell death. This type of necrosis is usually seen in tissues affected by ischemia, such as the heart, kidneys, and adrenal glands. However, it is not the typical pattern of necrosis seen in brain tissue.
Choice C Reason:
Caseous necrosis is a form of cell death in which the tissue maintains a cheese-like appearance. It is most commonly associated with tuberculosis infections in the lungs. This type of necrosis is not typically seen in brain tissue.
Choice D Reason:
Liquefactive necrosis is the correct answer. This type of necrosis occurs when the tissue becomes soft and liquefied, often forming a pus-filled cavity. It is commonly seen in the brain due to ischemic injury or bacterial infections. The high lipid content and low structural support in brain tissue make it particularly susceptible to liquefactive necrosis.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is D
Explanation
Choice A Reason:
Tertiary prevention focuses on managing and mitigating the complications of an existing disease to prevent further deterioration. For obesity, this might involve interventions like bariatric surgery or intensive management of comorbid conditions such as diabetes or cardiovascular disease. In this scenario, the goal is not to prevent the onset of disease but to manage its long-term effects and improve quality of life.
Choice B Reason:
Disease treatment refers to the direct management of a diagnosed condition. For a diabetic teen, this could include medications like insulin or metformin, regular monitoring of blood glucose levels, and other medical interventions to control diabetes. While a low-calorie diet and exercise are important components of diabetes management, they are more aligned with preventive measures rather than direct treatment.
Choice C Reason:
Secondary prevention aims to detect and address a disease early in its course to prevent progression. This might include screening programs, early interventions, and lifestyle modifications for individuals at high risk of developing a condition. In the context of diabetes, secondary prevention could involve regular blood glucose monitoring and early dietary changes to prevent the progression from prediabetes to diabetes.
Choice D Reason:
Primary prevention involves measures taken to prevent the onset of a disease before it occurs. This includes lifestyle interventions such as a healthy diet, regular physical activity, and maintaining a healthy weight. For an obese diabetic teen, a prescription for a low-calorie diet and exercise program is aimed at preventing further weight gain and reducing the risk of developing additional health complications, making it a primary prevention strategy.
Correct Answer is C
Explanation
Choice A Reason:
Hyperplasia refers to an increase in the number of cells in an organ or tissue, usually resulting in an increase in the size of the organ or tissue. This process is often a response to a stimulus and can be physiological or pathological. However, hyperplasia does not involve the replacement of one cell type with another, as seen in this case.
Choice B Reason:
Dysplasia is characterized by abnormal growth and development of cells within tissues or organs. It often indicates a precancerous condition and involves changes in cell size, shape, and organization. While dysplasia can occur in the respiratory tract, it does not describe the replacement of one type of epithelial cell with another.
Choice C Reason:
This is the correct answer. Metaplasia is the process by which one type of adult cell is replaced by another type of adult cell that is not typical for that tissue. In this case, the normal columnar ciliated cells in the bronchial airway have been replaced by stratified squamous epithelial cells, a common adaptation in response to chronic irritation from smoking.
Choice D Reason:
Hypertrophy refers to an increase in the size of cells, leading to an increase in the size of the affected organ or tissue. This process does not involve a change in cell type, making it an incorrect choice for this scenario.
Whether you are a student looking to ace your exams or a practicing nurse seeking to enhance your expertise , our nursing education contents will empower you with the confidence and competence to make a difference in the lives of patients and become a respected leader in the healthcare field.
Visit Naxlex, invest in your future and unlock endless possibilities with our unparalleled nursing education contents today
Report Wrong Answer on the Current Question
Do you disagree with the answer? If yes, what is your expected answer? Explain.
Kindly be descriptive with the issue you are facing.
