The nurse discovers a loop of the umbilical cord protruding through the vagina when preparing to perform a vaginal examination. The priority intervention is to:

Perform vaginal exam and apply upward digital pressure to the presenting part.

Immediately turn the client to her side.

Call the physician immediately.

Place a moist, clean towel over the cord to prevent drying.

Answer and Explanation

The Correct Answer is A

A. Perform vaginal exam and apply upward digital pressure to the presenting part. A prolapsed umbilical cord is an obstetric emergency that can lead to cord compression and fetal hypoxia. The priority intervention is for the nurse to manually lift the presenting part (usually the fetal head) off the cord to relieve pressure and restore blood flow. The nurse should maintain this position until an emergency cesarean section is performed.

B. Immediately turn the client to her side. Positioning changes, such as the knee-chest or Trendelenburg position, can help relieve pressure on the cord, but they are secondary to manually lifting the presenting part. While turning the client may assist, it is not the most immediate life-saving action.

C. Call the physician immediately. While notifying the provider is essential, relieving pressure on the umbilical cord takes priority. Delaying intervention to make a call could result in prolonged fetal hypoxia and compromise.

D. Place a moist, clean towel over the cord to prevent drying. Covering the cord with a moist towel helps prevent vasospasm and drying, but it does not relieve the compression that is cutting off oxygen to the fetus. The priority is to relieve pressure on the cord first before taking other measures.

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Correct Answer is D

Explanation

A. Maintaining euglycemia in labor reduces the need for insulin postpartum. While insulin requirements typically decrease after delivery due to the loss of placental hormones that cause insulin resistance, the primary reason for tight glucose control during labor is to prevent neonatal complications rather than reducing postpartum insulin needs.

B. A blood glucose level above 110 puts the client at risk for infection in labor. Poorly controlled diabetes can increase infection risk over time, but transient hyperglycemia in labor is not a direct cause of infection. The focus of glucose management during labor is to prevent neonatal hypoglycemia rather than maternal infection.

C. More insulin will be available for fetal use via placental transfer. Insulin does not cross the placenta, so maternal insulin therapy does not provide insulin to the fetus. However, maternal hyperglycemia leads to increased fetal insulin production, which can cause neonatal hypoglycemia after birth.

D. An elevated blood glucose in labor increases the risk of neonatal hypoglycemia. Maternal hyperglycemia causes the fetus to produce excessive insulin in utero. After birth, when the maternal glucose supply is suddenly cut off, the infant’s high insulin levels can cause a rapid drop in blood glucose, leading to neonatal hypoglycemia, which can be dangerous if not managed properly.

A. Maternal temperature of 101.4 F B. Maternal blood pressure of 138/89 C. Change in fetal baseline heart rate from 125 to 90 D. Change in the maternal pulse from 80 to 93

Correct Answer is C

Explanation

A. Maternal temperature of 101.4°F. A fever may indicate infection (chorioamnionitis), but it is not an immediate reason to stop oxytocin. The nurse should monitor for additional signs of infection and notify the provider, but the priority is fetal well-being.

B. Maternal blood pressure of 138/89. This blood pressure is not critically high and does not indicate a hypertensive crisis. Oxytocin can cause fluid retention and slight blood pressure changes, but this reading alone does not require stopping the infusion.

C. Change in fetal baseline heart rate from 125 to 90. A decrease in fetal heart rate (bradycardia) is a sign of fetal distress and requires immediate intervention. Oxytocin can cause uterine hyperstimulation, leading to decreased placental perfusion and fetal hypoxia. The priority is to stop oxytocin, reposition the mother, provide oxygen, and notify the provider.

D. Change in the maternal pulse from 80 to 93. A mild increase in heart rate is not uncommon during labor and may be due to pain, anxiety, or IV fluids. It does not indicate an emergency or the need to stop oxytocin.

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The nurse discovers a loop of the umbilical cord protruding through the vagina when preparing to perform a vaginal examination. The priority intervention is to:

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Naxlex Comprehensive Predictor Exams

A laboring woman with Type 1 diabetes is on an IV insulin drip, and the nurse is monitoring her glucose levels hourly. The woman's partner asks why the glucose needs to remain between 70-110 mg/dL. The nurse's response is based on which of the following information?

Correct Answer is D

Explanation

A nurse is monitoring the labor of a patient who is receiving IV oxytocin (Pitocin) at 6 ml/hr. Which of the following clinical signs would lead the nurse to stop the infusion?

Correct Answer is C

Explanation

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