The nurse is caring for a client whose arterial blood gas reveals partially compensated respiratory alkalosis. Which results are consistent with this finding?
Table 9.9 Normal Arterial Blood Gas Values |
ABG Value. Normal Value |
pH 7.35-7.45 |
PaCO2 35-45 mmHg |
HCO3- 22-26mEq/L |
Base excess -2 to +2 |
PaO2 80-95 mmHg |
SaO2 >95% |
pH 7.32, Pa02 88 mmHg, PaCO2 50 mmHg, HCO3 29 mEq/L, 02 sat 94%
pH 7.35, Pa02 98 mmHg, PaCO2 55 mmHg, HCO3 28 mEq/L, 02 sat 99%
pH 7.64, PaO2 94 mmHg, PaCO2 23 mmHg, HCO3 14 mEq/L, 02 sat 88%
PH 7.50, Pa02 91 mmHg, PaCO2 52 mmHg, HCO3 30 mEq/L, 02 sat 96%
The Correct Answer is C
A) pH 7.32, PaO2 88 mmHg, PaCO2 50 mmHg, HCO3 29 mEq/L, O2 sat 94%
This result suggests respiratory acidosis rather than respiratory alkalosis. In respiratory acidosis, the pH would be low (acidotic), PaCO2 would be elevated (since it reflects CO2 retention), and HCO3 would typically be elevated as a compensatory mechanism. This set of ABG values does not align with respiratory alkalosis, so it is not consistent with partially compensated respiratory alkalosis.
B) pH 7.35, PaO2 98 mmHg, PaCO2 55 mmHg, HCO3 28 mEq/L, O2 sat 99%
This set of values suggests respiratory acidosis, as indicated by a low pH (acidosis) and high PaCO2 (carbon dioxide retention). The HCO3 value is slightly elevated in compensation for respiratory acidosis, but this is not an example of partially compensated respiratory alkalosis, so it doesn't match the question's requirement.
C) pH 7.64, PaO2 94 mmHg, PaCO2 23 mmHg, HCO3 14 mEq/L, O2 sat 88%
This result is consistent with partially compensated respiratory alkalosis. In respiratory alkalosis, the pH would be elevated (alkalotic), PaCO2 would be low (indicating hyperventilation), and the kidneys would attempt to compensate by lowering bicarbonate (HCO3). In this case, the low PaCO2 (23 mmHg) and the low HCO3 (14 mEq/L) demonstrate partial compensation. The pH is also elevated at 7.64, which aligns with alkalosis. This is the correct answer for partially compensated respiratory alkalosis.
D) pH 7.50, PaO2 91 mmHg, PaCO2 52 mmHg, HCO3 30 mEq/L, O2 sat 96%
This result suggests respiratory acidosis with compensation. The elevated PaCO2 (52 mmHg) indicates CO2 retention, leading to acidosis, while the slightly elevated HCO3 (30 mEq/L) shows that the kidneys are compensating for the respiratory acidosis. The pH of 7.50 is slightly alkalotic, but it is more consistent with compensation for respiratory acidosis rather than respiratory alkalosis. Thus, this set of ABG values does not match the description of partially compensated respiratory alkalosis.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is D
Explanation
A. In the prone position:
The prone position has been shown to be beneficial in certain respiratory conditions, particularly in acute respiratory distress syndrome (ARDS), where it can help improve oxygenation by redistributing blood flow in the lungs. However, prone positioning is typically not the first choice for pneumonia, especially when it is localized to specific lobes of the lung. It is more commonly used in cases of diffuse bilateral lung injury or severe hypoxemia. Therefore, while prone positioning can improve oxygenation in ARDS, it is not specifically targeted for secretion removal in localized pneumonia.
B. In high-Fowler's position:
The high-Fowler's position (sitting up at a 60-90 degree angle) can help with dyspnea and promote lung expansion in conditions like heart failure or dyspneic states. However, for pneumonia, it is not as effective as lateral positioning for facilitating secretion drainage from specific lung lobes. The high-Fowler's position may be useful for promoting overall comfort and reducing dyspnea, but it is not the best position for improving secretion removal from the right middle and lower lobes.
C. On the left side:
Positioning the patient on the left side is not ideal for right middle and lower lobe pneumonia, as it would not optimize drainage from the affected lobes. The right middle and lower lobes are better drained when the patient is positioned on the right side, as gravity can help move the secretions from the affected lobes toward the larger airways for easier clearance.
D. On the right side: In the case of right middle and lower lobe pneumonia, positioning the client on the right side can help optimize ventilation and promote better secretion removal from the affected areas of the lung. This position allows gravity to assist in draining secretions from the right middle and lower lobes toward the larger airways, where they can be more easily cleared by coughing or suctioning. This positioning can improve oxygenation and facilitate secretion management, which is crucial for improving respiratory function in pneumonia.
Correct Answer is B
Explanation
A. Partially compensated metabolic alkalosis:
Metabolic alkalosis is characterized by elevated bicarbonate levels (HCO3), but in this case, the HCO3 is elevated (29 mEq/L), which suggests alkalosis. However, the PaCO2 is elevated at 47 mmHg, which is more consistent with a respiratory problem. A fully or partially compensated metabolic alkalosis would show a normal or low PaCO2 (due to respiratory compensation). Therefore, this option does not fit the ABG results.
B. Partially compensated respiratory acidosis: In this case, the pH is 7.17, which is low and indicates acidosis. The PaCO2 is 47 mmHg, which is elevated (normal range: 35-45 mmHg), indicating that the respiratory system is contributing to the acidosis. The HCO3 is 29 mEq/L, which is elevated (normal range: 22-26 mEq/L), suggesting a compensatory response from the kidneys to retain bicarbonate in an attempt to buffer the acidosis. Since the pH is still below normal and has not yet returned to the normal range (7.35-7.45), this suggests that the compensation is partial and the primary issue is respiratory acidosis.
C. Fully compensated metabolic alkalosis:
This answer is incorrect because metabolic alkalosis is not the primary disturbance here. Also, for a condition to be fully compensated, the pH would need to be within the normal range (7.35-7.45). Since the pH is 7.17, the condition is not fully compensated.
D. Fully compensated respiratory acidosis:
For fully compensated respiratory acidosis, the pH should be within the normal range, as the kidneys would have fully compensated for the elevated PaCO2. Since the pH is 7.17, this is a sign of partial compensation, not full compensation. Therefore, this option is incorrect.
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