The nurse is caring for a patient with stage IV Hodgkin disease. Where should the nurse expect to find enlarged lymph nodes during the assessment?
Two areas of lymph nodes above and below the diaphragm
Two or more areas on the same side of the diaphragm
Localized in the cervical neck area only
Generalized throughout the body within multiple organs
The Correct Answer is D
A. Two areas of lymph nodes above and below the diaphragm: This describes stage III Hodgkin disease, where lymph node involvement occurs both above and below the diaphragm, but not necessarily in multiple organs.
B. Two or more areas on the same side of the diaphragm: This corresponds to stage II Hodgkin disease, which is limited to two or more lymph node regions on the same side of the diaphragm.
C. Localized in the cervical neck area only: Stage I Hodgkin disease typically involves a single lymph node region, often the cervical nodes, without generalized or extensive spread.
D. Generalized throughout the body within multiple organs: In stage IV Hodgkin disease, the cancer has spread beyond the lymph nodes to other organs and tissues, leading to generalized lymphadenopathy and potential organ involvement.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
A. Progressive increase in platelet production: In DIC, platelets are rapidly consumed, not increased, due to widespread clotting in the blood vessels.
B. Excessive thrombosis and bleeding: DIC is a complex condition where there is widespread activation of the clotting cascade, leading to excessive clotting and subsequent depletion of platelets and clotting factors, resulting in both thrombosis and bleeding.
C. Immediate sodium and fluid retention: Sodium and fluid retention are not specific findings in DIC; they may occur in cases of renal or heart failure but are unrelated to the clotting issues in DIC.
D. Increased clotting factors: In DIC, clotting factors are depleted as they are used up in widespread clotting, leading to bleeding when factors are exhausted.
Correct Answer is ["28"]
Explanation
Flowrate= Total volume ml×Drop factor÷Time
= (1000 × 10) ÷ 360
= 27.78
≈ 28 gtt/min
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