The nurse obtains a monitor strip on a patient who has had a myocardial infarction and makes the following analysis: P wave not apparent, ventricular rate 196, R-R interval regular, P-R interval not measurable, QRS complex wide and distorted, QRS duration 0.18 second. The nurse interprets the patient's cardiac rhythm as;
ventricular tachycardia.
atrial fibrillation.
atrial tachycardia.
ventricular fibrillation.
The Correct Answer is A
The characteristics described in the monitor strip analysis suggest ventricular tachycardia. The absence of a visible P wave and the wide and distorted QRS complex indicates that the electrical impulse is originating in the ventricles rather than the atria. The ventricular rate of 196 and regular R-R intervals further support the diagnosis of ventricular tachycardia.
B. Atrial fibrillation in (option B) is incorrect because it is characterized by irregularly irregular R-R intervals and the absence of discernible P waves. The QRS complex is typically narrow
C. Atrial tachycardia in (option C) is incorrect because it would have a rapid atrial rate with regular R-R intervals, and P waves may or may not be discernible. The QRS complex is typically narrow.
D. Ventricular fibrillation in (option D) is incorrect because it would present as a chaotic, rapid, and irregular electrical activity with no discernible P waves, QRS complexes, or regular R-R intervals. It is a life-threatening emergency that requires immediate defibrillation.
Therefore, based on the provided information, the nurse would interpret the patient's cardiac rhythm as ventricular tachycardia. However, it is important to note that an accurate interpretation should be made by a qualified healthcare professional, and the patient's clinical context should also be considered.

Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
Assessing the patient's level of consciousness is a critical initial step in evaluating a patient with shock. Altered mental status or decreased level of consciousness can be indicative of inadequate cerebral perfusion and may require immediate interventions to address compromised brain function and ensure patient safety.
While all the options mentioned are important in the assessment and management of a patient in shock, checking the level of consciousness takes priority as it provides essential information about the patient's neurological status and helps guide further interventions.
A. Obtaining the blood pressure in (option A) is incorrect because Assessing blood pressure is crucial in evaluating a patient in shock, but it can be done in conjunction with checking the level of consciousness and other vital signs.
C. Administering oxygen in (option C) is incorrect because: Administering oxygen is important in managing shock, as tissue hypoxia is a key concern. However, it can be done simultaneously with assessing the level of consciousness and initiating other interventions.
D. Obtaining a 12-lead electrocardiogram (ECG) in (option D) is incorrect because While an ECG may provide valuable information about the patient's cardiac function, it is not the first priority in a patient with shock of unknown etiology. Assessing the level of consciousness and vital signs takes precedence.
Correct Answer is ["9"]
Explanation
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Doseinmcg/min=2mcg/kg/min×60kg=120mcg/min
Convert this to mg/min since the concentration is in mg:
120mcg/min=0.12mg/min120 \text{ mcg/min} = 0.12 \text{ mg/min}120mcg/min=0.12mg/min
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Determine the concentration of Dopamine:
- Total amount of Dopamine: 200 mg in 250 mL of saline
- Concentration:
Concentration=200mg250mL=0.8mg/mL\text{Concentration} = \frac{200 \text{ mg}}{250 \text{ mL}} = 0.8 \text{ mg/mL}Concentration=250mL200mg=0.8mg/mL
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Calculate the pump rate in mL/min:
To find the rate in mL/min needed to deliver 0.12 mg/min:
Pumprate=Desireddose(mg/min)Concentration(mg/mL)\text{Pump rate} = \frac{\text{Desired dose (mg/min)}}{\text{Concentration (mg/mL)}}Pumprate=Concentration(mg/mL)Desireddose(mg/min)
Pumprate=0.12mg/min0.8mg/mL=0.15mL/min\text{Pump rate} = \frac{0.12 \text{ mg/min}}{0.8 \text{ mg/mL}} = 0.15 \text{ mL/min}Pumprate=0.8mg/mL0.12mg/min=0.15mL/min
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Convert the pump rate to mL/hour:
Multiply by 60 to convert from mL/min to mL/hour:
Pumprate=0.15mL/min×60min/hour=9mL/hour\text{Pump rate} = 0.15 \text{ mL/min} \times 60 \text{ min/hour} = 9 \text{ mL/hour}Pumprate=0.15mL/min×60min/hour=9mL/hour
So, you should set the pump to deliver Dopamine at a rate of 9 mL/hour.
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