When planning the care for a client during the first 24 hours postpartum, the nurse expects to monitor the client's pulse and blood pressure frequently based on the understanding that the client is at risk for which condition?
Thromboembolism
Cervical laceration
Hemorrhoids
Hemorrhage
The Correct Answer is D
Hemorrhage. This is because postpartum hemorrhage (PPH) is severe bleeding and loss of blood after childbirth that can lead to death. The most common cause of PPH is the uterus not contracting properly after delivery. The nurse needs to monitor the client’s pulse and blood pressure frequently to detect signs of shock and blood loss.
Choice A is wrong because thromboembolism is a blood clot that blocks a blood vessel, not a complication of bleeding.
Choice B is wrong because cervical laceration is a tear in the cervix that can cause bleeding, but it is not a common cause of PPH.
Choice C is wrong because hemorrhoids are swollen veins in the anus or rectum that can cause bleeding, but they are not a common cause of PPH.
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Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
Place the infant on the mother's abdomen after birth. This will help the infant maintain an adequate body temperature by providing skin-to-skin contact with the mother, which reduces heat loss and promotes bonding. Skin-to-skin contact also stimulates the baby's natural feeding cues and helps initiate breastfeeding.
Choice A is not correct because turning up the temperature in the birth room may not be enough to prevent heat loss from the infant, especially if they are wet or exposed to cold surfaces. It may also make the mother uncomfortable or dehydrated.
Choice B is not correct because bathing the infant immediately after birth may increase heat loss from evaporation and conduction. It may also interfere with the baby's natural protective coating (vernix) and microbiome. Bathing should be delayed until at least 24 hours after birth.
Choice D is not correct because wrapping the infant in a warm, dry blanket may not provide the same benefits as skin-to-skin contact with the mother. It may also prevent the baby from smelling and seeing the mother's breast, which are important cues for breastfeeding initiation.
Correct Answer is A
Explanation
Asymmetrical chest movement is a sign of respiratory distress in the newborn, as it indicates unequal lung expansion or airway obstruction. A respiratory rate of 50 breaths/minute (choice B) is normal for a newborn, as is acrocyanosis (choice C), which is a bluish discoloration of the hands and feet due to immature peripheral circulation. Short periods of apnea (less than 15 seconds) (choice D) are also common and benign in newborns unless they are associated with bradycardia or cyanosis.
Choice B is not correct because a respiratory rate of 50 breaths/minute is within the normal range for a newborn.
Choice C is not correct because acrocyanosis is a normal finding in newborns and does not indicate respiratory distress.
Choice D is not correct because short periods of apnea (less than 15 seconds) are normal in newborns and do not indicate respiratory distress.
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