Which infant would be more likely to have Rh incompatibility?
Infant of an Rh-negative mother and a father who is Rh-positive and homozygous for the Rh factor.
Infant who is Rh negative and whose mother is Rh negative.
Infant of an Rh-negative mother and a father who is Rh-positive and heterozygous for the Rh factor.
Infant who is Rh positive and whose mother is Rh positive.
The Correct Answer is A
choice A.
Infant of an Rh-negative mother and a father who is Rh-positive and homozygous for the Rh factor.
Rh incompatibility occurs when a woman is Rh-negative and her baby is Rh-positive. This can cause hemolytic disease of the neonate (HDN), a condition where the mother’s antibodies destroy the baby’s red blood cells.
Choice B is wrong because if both the mother and the baby are Rh-negative, there is no risk of Rh incompatibility.
Choice C is wrong because if the father is heterozygous for the Rh factor, there is a 50% chance that the baby will be Rh-negative and not affected by Rh incompatibility.
Choice D is wrong because if both the mother and the baby are Rh-positive, there is no risk of Rh incompatibility.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
Placing eye shields over the newborn’s closed eyes. This is because phototherapy can cause eye damage and irritation to the newborn, so eye protection is essential.
Choice A is wrong because oil-based lotion can increase the absorption of heat and cause burns to the newborn’s skin.
Choice B is wrong because limiting the newborn’s intake of milk can cause dehydration and increase the risk of hyperbilirubinemia.
Choice D is wrong because changing the newborn’s position every 4 hours is not frequent enough to prevent pressure ulcers and ensure even exposure to the light.
Normal ranges for bilirubin levels in newborns are 1 to 12 mg/dL for term infants and 3 to 14 mg/dL for preterm infants. Phototherapy is usually indicated when the bilirubin level exceeds 15 mg/dL for term infants and 10 mg/dL for preterm infants.
Correct Answer is B
Explanation
This is because a patent ductus arteriosus is a congenital heart defect that involves a defect in which the fetal shunt between the aorta and the pulmonary artery fails to close. This causes a continuous machinery-like murmur that can be heard on auscultation.
Choice A is wrong because pulmonary stenosis is a narrowing of the pulmonary valve or artery that obstructs blood flow to the lungs. It causes a systolic ejection murmur that is best heard at the upper left sternal border.
Choice C is wrong because the ventricular septal defect is a hole in the wall between the ventricles that allows blood to flow from the left to the right side of the heart. It causes a loud, harsh holosystolic murmur that is best heard at the left lower sternal border.
Choice D is wrong because coarctation of the aorta is a narrowing of the aorta that reduces blood flow to the lower body. It causes a systolic murmur that radiates to the back and weak or absent femoral pulses.
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