A 15 kg child has a urine output of 360 mL during the past 12 hours. Calculate the child’s urine output in mL/kg/hour for this period of time. (Do not enter units).
The Correct Answer is ["2"]
Calculation Steps
Step 1: Determine the total urine output in mL.
- Total urine output = 360 mL
Step 2: Determine the child’s weight in kg.
- Weight = 15 kg
Step 3: Determine the time period in hours.
- Time = 12 hours
Step 4: Calculate the urine output in mL/kg/hour.
- Urine output (mL/kg/hour) = Total urine output ÷ (Weight × Time)
Step 5: Perform the multiplication inside the parentheses first.
- Weight × Time = 15 kg × 12 hours = 180 kg·hours
Step 6: Perform the division.
- Urine output (mL/kg/hour) = 360 mL ÷ 180 kg·hours = 2 mL/kg/hour
Result
The child’s urine output is 2 mL/kg/hour.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
The correct answer is b. 25%.
Choice A: 50%
If both parents are heterozygous for the sickle cell trait (carriers), each child has a 50% chance of inheriting one sickle cell gene from one parent and a normal gene from the other parent. This would make the child a carrier of the sickle cell trait, not someone with sickle cell anemia. Therefore, the chance of having sickle cell anemia is not 50%.
Choice B: 25%
When both parents are carriers of the sickle cell trait (heterozygous), there is a 25% chance that their child will inherit two sickle cell genes (one from each parent), resulting in sickle cell anemia. This is because each parent has one normal hemoglobin gene (A) and one sickle cell gene (S). The possible combinations for their children are AA (normal), AS (carrier), SA (carrier), and SS (sickle cell anemia). The probability of the SS combination is 25%.
Choice C: 75%
A 75% chance is not accurate in this scenario. The 75% figure might be mistakenly considered if one were to add the probabilities of being a carrier (50%) and having sickle cell anemia (25%). However, these probabilities are distinct and should not be combined in this manner.
Choice D: 100%
A 100% chance would imply that every child of the couple would have sickle cell anemia, which is not the case. Since each parent is a carrier, there is only a 25% chance for each child to have sickle cell anemia. The remaining 75% of the time, the child will either be a carrier or have normal hemoglobin.
Correct Answer is A
Explanation
Choice A reason:
Cleansing the suture line, maintaining an upright position, and using arm restraints are crucial aspects of postoperative care for an infant after cleft lip repair. Cleansing the suture line helps prevent infection and promotes healing. Keeping the infant in an upright position reduces the risk of aspiration and helps with breathing. Arm restraints prevent the infant from touching or rubbing the surgical site, which could disrupt the healing process.
Choice B Reason:
Mouth irrigations and a prone position are not recommended for postoperative care after cleft lip repair. Mouth irrigations can be too harsh for the delicate surgical site, and a prone position (lying face down) can increase the risk of aspiration and breathing difficulties. Cleansing the suture line is important, but the other aspects of this choice are not suitable.
Choice C Reason:
Frequent oral suction and spoon feeding are not appropriate for an infant after cleft lip repair. Oral suction can be too aggressive and may damage the surgical site. Spoon feeding is not recommended as it can put pressure on the healing lip. Giving a teething toy is also not advisable as it can cause the infant to put objects in their mouth, potentially harming the surgical site.
Choice D Reason:
Arm restraints are indeed necessary to prevent the infant from touching the surgical site. However, postural drainage and mouth irrigations are not suitable for postoperative care after cleft lip repair. Postural drainage is not relevant to this condition, and mouth irrigations can be too harsh for the healing tissue.
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