A nurse is preparing to administer naloxone 10 mcg/kg via IV bolus to a client who weighs 220 lb. The amount available is 0.4 mg/mL. How many mL should the nurse administer? (round off to the nearest tenth)
2.5 mL.
25 mL.
2.05 mL.
2.25 mL.
The Correct Answer is A
Let’s break down the problem step by step:
Step 1: Convert the client’s weight from pounds (lb) to kilograms (kg). We know that 1 kg = 2.2 lbs. So, we have: 220 lb ÷ 2.2 = 100 kg
Step 2: Calculate the total amount of naloxone needed. The doctor ordered 10 mcg/kg, and the client weighs 100 kg. So, we have: 10 mcg/kg × 100 kg = 1000 mcg
Step 3: Convert micrograms (mcg) to milligrams (mg). We know that 1 mg = 1000 mcg. So, we have: 1000 mcg ÷ 1000 = 1 mg
Step 4: Calculate the volume of naloxone solution needed. The available naloxone solution is 0.4 mg/mL. So, we have: 1 mg ÷ 0.4 = 2.5 mL
So, the nurse should administer 2.5 mL of naloxone. Since we are asked to round off to the nearest tenth, the final answer remains 2.5 mL.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
Step 1: 100 mL ÷ 30 min
Step 2: (100 mL ÷ 30 min) × 60 min/hr
Step 3: 3.33 mL/min × 60 min/hr
Answer: 200 mL/hr
Correct Answer is C
Explanation

The fluctuation of fluid in the water-seal chamber of a chest tube is known as tidaling and is caused by the changes in pressure within the chest during respiration.
Choice A is not correct because tidaling does not indicate an air leak.
Choice B is not correct because tidaling does not necessarily mean that the lung is fully re-expanded.
Choice D is not correct because suction pressure does not cause tidaling.
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