Which statement is true concerning osteogenesis imperfecta (OI)?
OI is easily treated
With a later onset, the disease usually runs a more difficult course
Braces and PT exercises are of no therapeutic value
OI is an inherited disorder
The Correct Answer is D
Choice A: OI is Easily Treated
Osteogenesis imperfecta (OI) is not easily treated. It is a genetic disorder characterized by fragile bones that break easily. While there are treatments available to manage symptoms and improve quality of life, there is no cure for OI1. Treatments include medications to strengthen bones, physical therapy, and surgical procedures.
Choice B: With a Later Onset, the Disease Usually Runs a More Difficult Course
The severity of osteogenesis imperfecta can vary widely, but it is not necessarily true that a later onset leads to a more difficult course. The course of the disease depends on the type of OI and the specific genetic mutation involved. Some types of OI are more severe and present earlier in life, while others are milder and may not be diagnosed until later.
Choice C: Braces and PT Exercises are of No Therapeutic Value
This statement is incorrect. Braces and physical therapy (PT) exercises are valuable in managing osteogenesis imperfecta. Physical therapy helps in building muscle strength, improving joint movement, and preventing fractures. Braces can provide support for weak muscles, decrease pain, and keep joints properly aligned.
Choice D: OI is an Inherited Disorder
This statement is true. Osteogenesis imperfecta is a genetic disorder that is usually inherited in an autosomal dominant pattern. This means that a person only needs one copy of the defective gene from one parent to inherit the disorder. In some cases, OI can also occur due to a spontaneous mutation.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["2"]
Explanation
Calculation Steps
Step 1: Determine the total urine output in mL.
- Total urine output = 360 mL
Step 2: Determine the child’s weight in kg.
- Weight = 15 kg
Step 3: Determine the time period in hours.
- Time = 12 hours
Step 4: Calculate the urine output in mL/kg/hour.
- Urine output (mL/kg/hour) = Total urine output ÷ (Weight × Time)
Step 5: Perform the multiplication inside the parentheses first.
- Weight × Time = 15 kg × 12 hours = 180 kg·hours
Step 6: Perform the division.
- Urine output (mL/kg/hour) = 360 mL ÷ 180 kg·hours = 2 mL/kg/hour
Result
The child’s urine output is 2 mL/kg/hour.
Correct Answer is B
Explanation
The correct answer is b. 25%.
Choice A: 50%
If both parents are heterozygous for the sickle cell trait (carriers), each child has a 50% chance of inheriting one sickle cell gene from one parent and a normal gene from the other parent. This would make the child a carrier of the sickle cell trait, not someone with sickle cell anemia. Therefore, the chance of having sickle cell anemia is not 50%.
Choice B: 25%
When both parents are carriers of the sickle cell trait (heterozygous), there is a 25% chance that their child will inherit two sickle cell genes (one from each parent), resulting in sickle cell anemia. This is because each parent has one normal hemoglobin gene (A) and one sickle cell gene (S). The possible combinations for their children are AA (normal), AS (carrier), SA (carrier), and SS (sickle cell anemia). The probability of the SS combination is 25%.
Choice C: 75%
A 75% chance is not accurate in this scenario. The 75% figure might be mistakenly considered if one were to add the probabilities of being a carrier (50%) and having sickle cell anemia (25%). However, these probabilities are distinct and should not be combined in this manner.
Choice D: 100%
A 100% chance would imply that every child of the couple would have sickle cell anemia, which is not the case. Since each parent is a carrier, there is only a 25% chance for each child to have sickle cell anemia. The remaining 75% of the time, the child will either be a carrier or have normal hemoglobin.
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