The diet of a child with chronic renal failure is usually characterized as:.
Supplemented with vitamins A, E, and K.
High in protein.
Low in vitamin D.
Low in phosphorus.
The Correct Answer is D
The correct answer is choice D: Low in phosphorus.
Choice A rationale:
Supplemented with vitamins A, E, and K is not the characteristic of the diet for a child with chronic renal failure. While vitamin supplementation might be necessary in some cases, the primary dietary considerations in chronic renal failure are related to managing electrolyte imbalances, fluid retention, and waste buildup due to compromised kidney function.
Choice B rationale:
High in protein is not the recommended characteristic of the diet for a child with chronic renal failure. Kidneys affected by chronic renal failure have a reduced ability to filter and excrete waste products from protein metabolism. Excessive protein intake can lead to the accumulation of nitrogenous waste products, potentially worsening the condition and contributing to uremia.
Choice C rationale:
Low in vitamin D is not the primary characteristic of the diet for a child with chronic renal failure. Vitamin D metabolism can be affected by kidney dysfunction, but the focus of the diet in chronic renal failure is primarily on managing electrolyte levels, particularly phosphorus and potassium, as well as controlling fluid intake.
Choice D rationale:
Low in phosphorus is the correct characteristic of the diet for a child with chronic renal failure. Impaired kidney function in chronic renal failure leads to difficulty in excreting phosphorus, which can result in elevated blood phosphorus levels. High phosphorus levels can contribute to bone and mineral disorders and cardiovascular complications. Therefore, a diet low in phosphorus is crucial to prevent these complications and manage the progression of the disease.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
The correct answer is choice B: Pulmonic stenosis, ventricular septal defect, overriding aorta, right ventricular hypertrophy.
Choice A rationale:
Pulmonic stenosis, ventricular septal defect, aortic hypertrophy, left ventricular hypertrophy. This choice is incorrect because it includes "aortic hypertrophy" and "left ventricular hypertrophy," which are not components of the tetralogy of Fallot. Aortic hypertrophy is not a recognized structural defect in tetralogy of Fallot, and left ventricular hypertrophy is not a characteristic feature of this congenital heart condition.
Choice B rationale:
Pulmonic stenosis, ventricular septal defect, overriding aorta, right ventricular hypertrophy. This is the correct choice. Tetralogy of Fallot is characterized by four specific structural defects: pulmonic stenosis (narrowing of the pulmonary valve), ventricular septal defect (hole between the right and left ventricles), overriding aorta (aorta positioned over the ventricular septal defect, receiving blood from both ventricles), and right ventricular hypertrophy (enlargement of the right ventricle due to increased workload).
Choice C rationale:
Aortic stenosis, ventricular septal defect, overriding aorta, right ventricular hypertrophy. This choice is incorrect because it includes "aortic stenosis," which is not part of the tetralogy of Fallot. In tetralogy of Fallot, the stenosis occurs at the pulmonary valve, not the aortic valve.
Choice D rationale:
Aortic stenosis, atrial septal defect, overriding aorta, left ventricular hypertrophy. This choice is incorrect. While "overriding aorta" is present in tetralogy of Fallot, "atrial septal defect" and "left ventricular hypertrophy" are not part of this condition. Atrial septal defects involve a hole between the two atria, not the ventricles, and left ventricular hypertrophy is not typically seen in tetralogy of Fallot.
Correct Answer is ["2.6"]
Explanation
Step 1: Calculate the total mg per dose. 325 mg × 2 tablets = 650 mg
Step 2: Calculate the number of doses in 24 hours. 24 hours ÷ 6 hours = 4 doses
Step 3: Calculate the total mg in 24 hours. 650 mg × 4 doses = 2600 mg
Step 4: Convert mg to grams. 2600 mg ÷ 1000 = 2.6
Answer: 2.6
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