The nurse is monitoring a child with hydrocephalus who received a repeat ventriculoperitoneal (VP) shunt yesterday. Which assessment finding indicates to the nurse that the shunt is functioning normally?
The child has grown in height since the previous shunt placement.
The child is afebrile with normal vital signs postoperatively.
An intracranial pressure (ICP) monitoring probe is in place.
The child reports no evidence of continuous headaches.
The Correct Answer is D
The absence of continuous headaches in the child indicates that the VP shunt is functioning normally. A VP shunt is used to treat hydrocephalus by draining excess cerebrospinal fluid from the brain to the abdomen. If the shunt is functioning properly, it should relieve pressure on the brain and reduce symptoms such as headaches. The other options (A, B, and C) do not directly indicate whether the shunt is functioning normally or not.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
To maintain normal growth and development of an infant with a repaired gastroschisis who is receiving parenteral nutrition and continuous enteral feedings, the nurse should include offering a pacifier for non- nutritive sucking in the plan of care. Non-nutritive sucking can help promote the development of the infant's oral motor skills and support normal feeding behaviors. The other options (B, C, and D) are not directly related to maintaining normal growth and development in this situation.
Correct Answer is ["1.8"]
Explanation
The nurse should administer 1.8 mL of diazepam.
To calculate the volume of diazepam to be administered, you would first calculate the total dose of diazepam for this child by multiplying the child's weight (30 kg) by the prescribed dose (0.3 mg/kg). This calculation gives a total dose of 9 mg (30 kg x 0.3 mg/kg = 9 mg). Next, you would divide the total dose (9 mg) by the concentration of the medication (5 mg/mL) to determine the volume to be administered. This calculation gives a volume of 1.8 mL (9 mg / 5 mg/mL = 1.8 mL).
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