The older adult client diagnosed with Parkinson's disease (PD) has been prescribed the combination medication carbidopa/levodopa. Which data indicates the medication is effective?
The client is able to walk upright without stumbling.
The client eats 30% to 40% of meals within 1 hour.
The client does not display emotions when discussing the illness.
The client has cogwheel motion when swinging the arms.
The Correct Answer is A
Carbidopa/levodopa is a medication used to treat the symptoms of Parkinson's disease, including tremors, stiffness, and difficulty with movement. If the medication is effective, the client should show improvement in their ability to move and perform daily activities. In this case, the client being able to walk upright without stumbling indicates that the medication is effective.
Option B is incorrect because eating 30% to 40% of meals within 1 hour is not related to the effectiveness of carbidopa/levodopa.
Option C is incorrect because displaying emotions when discussing the illness is not related to the effectiveness of carbidopa/levodopa.
Option D is incorrect because cogwheel motion when swinging the arms is a symptom of Parkinson's disease and would indicate that the medication is not effective.
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Related Questions
Correct Answer is D
Explanation
Flumazenil is a benzodiazepine antagonist that can be used as an antidote for lorazepam overdose ¹. It works by reversing the effects of benzodiazepines such as lorazepam ¹.
Option A is not correct because naloxone is an opioid antagonist and is not used to treat benzodiazepine overdose.
Option B is not correct because acetylcysteine is used to treat acetaminophen overdose and is not used to treat benzodiazepine overdose.
Option C is not correct because physostigmine is used to treat anticholinergic toxicity and is not used to treat benzodiazepine overdose.
Correct Answer is A
Explanation
The half-life of a medication is the time it takes for the concentration of the medication in the body to decrease by half. In this case, the medication has a half-life of 2 hours and a current toxic level of 40 mEq/dL. After 2 hours, the level will decrease to 20 mEq/dL. After another 2 hours (4 hours total), the level will decrease to 10 mEq/dL, which is within the normal range. However, it will take another 21 half-lives (42 hours) for the level to reach 5 mEq/dL, which is the lower end of the normal range. Therefore, it will take a total of 25 hours (4 + 21) for the medication to reach the normal range.
Option B is incorrect because it would take much longer than 24 hours for the medication to reach the normal range.
Option C is incorrect because it would only take 2 hours for the medication to decrease by half, not reach the normal range.
Option D is incorrect because it would take longer than 4 hours for the medication to reach the normal range.
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