A first-response team is working at the location of a bombing incident. A nurse triaging a group of clients should give treatment priority to which of the following clients?
A client who has a femur fracture with a 2+ pedal pulse
A client who has superficial partial-thickness burn injuries over 5% of his body
A client who is ambulatory and exhibits manic behavior
A client who has a rigid abdomen with manifestations of shock
The Correct Answer is D
A. A femur fracture with a 2+ pedal pulse indicates adequate circulation and is not immediately life-threatening.
B. Superficial burns, while painful, are not immediately life-threatening unless covering a significant portion of the body.
C. Ambulatory with manic behavior suggests psychological distress but not immediate life-threatening physical condition.
D. A rigid abdomen with signs of shock indicates potential internal bleeding or organ injury requiring immediate attention.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
A. Providing nutrition education is a form of primary prevention aimed at preventing the development of obesity-related health issues.
B. Screening for hearing loss in employees exposed to high levels of noise is a secondary prevention strategy, as it aims to detect and address health issues early to prevent further complications.
C. Providing education about safety and injury prevention is a primary prevention strategy designed to prevent injuries before they occur.
D. Coordinating disaster planning efforts is a preparedness measure and does not specifically fall under secondary prevention.
Correct Answer is D
Explanation
A. Prevalence proportion is calculated as (Number of cases / Population) × 100,000. For this community, it would be (11 / 15,000) × 100,000 = 73.3/100,000.
B. Prevalence proportion is calculated as (Number of cases / Population) × 100,000. For this community, it would be (11 / 15,000) × 100,000 = 73.3/100,000.
C. Prevalence proportion is calculated as (Number of cases / Population) × 100,000. For this community, it would be (11 / 15,000) × 100,000 = 73.3/100,000.
D. Prevalence proportion is calculated as (Number of cases / Population) × 100,000. For this community, it would be (11 / 15,000) × 100,000 = 73.3/100,000.
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