A NICU nurse is completing an assessment on a premature infant male born at 29 weeks gestation. It is noted that the male infant has no palpable testes in the scrotum. The nurse should:
Document this expected finding.
Insert a urinary catheter to collect a urine specimen.
Initiate a social work consult.
Call the provider for this unexpected finding.
The Correct Answer is A
Choice A reason:
In premature infants, it is common for the testes to not be palpable in the scrotum at birth. This condition, known as cryptorchidism, affects about 30% of preterm infants1. The testes usually descend into the scrotum by the time the infant reaches term or within the first few months of life. Therefore, the nurse should document this as an expected finding and continue to monitor the infant’s development.
Choice B reason:
Inserting a urinary catheter to collect a urine specimen is not necessary in this situation. The absence of palpable testes in a premature infant is a common finding and does not indicate a need for immediate urinary evaluation. Urinary catheterization should be reserved for specific medical indications, such as suspected urinary tract infection or urinary retention.
Choice C reason:
Initiating a social work consult is not relevant to the clinical finding of undescended testes in a premature infant. Social work consultations are typically initiated for psychosocial issues, family support, or discharge planning. The absence of palpable testes is a medical finding that should be documented and monitored by the healthcare team.
Choice D reason:
Calling the provider for this unexpected finding is not necessary because the absence of palpable testes in a premature infant is an expected finding. The nurse should document the finding and continue to monitor the infant’s development. If the testes do not descend by the time the infant reaches term or within the first few months of life, further evaluation and management may be needed.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
Choice A reason:
Bacteriuria, or the presence of bacteria in the urine, is not typically associated with acute glomerulonephritis. Acute glomerulonephritis is primarily an inflammatory condition affecting the glomeruli of the kidneys, and it does not usually involve bacterial infection. Increased specific gravity can occur due to concentrated urine, but bacteriuria is not a characteristic finding.
Choice B reason:
Hematuria, or blood in the urine, and mild to moderate proteinuria are characteristic findings in acute glomerulonephritis. Hematuria occurs due to inflammation and damage to the glomeruli, allowing red blood cells to pass into the urine. Proteinuria results from the increased permeability of the glomerular basement membrane, allowing proteins to leak into the urine. These findings are key indicators of glomerular inflammation and damage.
Choice C reason:
While proteinuria can be present in acute glomerulonephritis, bacteriuria is not a typical finding. The condition is primarily inflammatory rather than infectious, so the presence of bacteria in the urine is not expected. The focus should be on the inflammatory markers such as hematuria and proteinuria.
Choice D reason:
High levels of proteinuria and decreased specific gravity are not typical findings in acute glomerulonephritis. While proteinuria can occur, it is usually mild to moderate rather than high. Specific gravity may be increased due to concentrated urine, but decreased specific gravity is not a characteristic finding of this condition.
Correct Answer is ["2"]
Explanation
Calculation Steps
Step 1: Determine the total urine output in mL.
- Total urine output = 360 mL
Step 2: Determine the child’s weight in kg.
- Weight = 15 kg
Step 3: Determine the time period in hours.
- Time = 12 hours
Step 4: Calculate the urine output in mL/kg/hour.
- Urine output (mL/kg/hour) = Total urine output ÷ (Weight × Time)
Step 5: Perform the multiplication inside the parentheses first.
- Weight × Time = 15 kg × 12 hours = 180 kg·hours
Step 6: Perform the division.
- Urine output (mL/kg/hour) = 360 mL ÷ 180 kg·hours = 2 mL/kg/hour
Result
The child’s urine output is 2 mL/kg/hour.
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