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For the same child weighing 36 kg in moderate dehydration, now calculate the volume of ORS they should receive every 15 minutes. (Do not enter units)
Which foods should a child with celiac disease include in their diet?

A.

Rye and oats

B.

Wheat and corn

C.

Rice and soy

D.

Barley and millet grain

Answer and Explanation

The Correct Answer is C

Choice A reason:

Rye and oats: Rye contains gluten, which must be avoided by individuals with celiac disease. Oats, while naturally gluten-free, can often be contaminated with gluten during processing. Therefore, they should be introduced cautiously and only if labeled gluten-free.

Choice B Reason:

Wheat and corn: Wheat is a major source of gluten and must be strictly avoided by those with celiac disease. Corn, on the other hand, is naturally gluten-free and safe for consumption. However, since wheat is included in this option, it is not suitable for a gluten-free diet.

Choice C Reason:

Rice and soy: Both rice and soy are naturally gluten-free and safe for individuals with celiac disease. They are excellent alternatives to gluten-containing grains and provide essential nutrients.

Choice D Reason:

Barley and millet grain: Barley contains gluten and must be avoided by those with celiac disease. Millet is naturally gluten-free and safe for consumption. However, since barley is included in this option, it is not suitable for a gluten-free diet.


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Related Questions

Correct Answer is ["20"]

Explanation

Calculation Steps

Step 1: Determine the child’s weight in kg.

  • Weight = 23 kg

Step 2: Determine the time period in hours.

  • Time = 60 minutes = 1 hour

Step 3: Calculate the bolus rate in mL/kg/hour.

  • Bolus rate (mL/kg/hour) = Total volume (mL) ÷ (Weight × Time)

Step 4: Assume a standard bolus volume for severe dehydration, which is typically 20 mL/kg.

  • Total volume = 20 mL/kg × 23 kg = 460 mL

Step 5: Calculate the bolus rate.

  • Bolus rate (mL/kg/hour) = 460 mL ÷ (23 kg × 1 hour) = 20 mL/kg/hour

Result

The bolus rate to be given to the severely dehydrated child is 20 mL/kg/hour.

Correct Answer is ["2"]

Explanation

Calculation Steps

Step 1: Determine the total urine output in mL.

  • Total urine output = 360 mL

Step 2: Determine the child’s weight in kg.

  • Weight = 15 kg

Step 3: Determine the time period in hours.

  • Time = 12 hours

Step 4: Calculate the urine output in mL/kg/hour.

  • Urine output (mL/kg/hour) = Total urine output ÷ (Weight × Time)

Step 5: Perform the multiplication inside the parentheses first.

  • Weight × Time = 15 kg × 12 hours = 180 kg·hours

Step 6: Perform the division.

  • Urine output (mL/kg/hour) = 360 mL ÷ 180 kg·hours = 2 mL/kg/hour

Result

The child’s urine output is 2 mL/kg/hour.

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